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Jlenok [28]
2 years ago
15

You observe that a negatively charged plastic pen repels a charged piece of magic tape. You then observe that the same piece of

tape is repelled when brought near a small metal sphere. You are wearing rubber soled shoes, and you touch the metal sphere with your hand. After you touch the metal sphere, you observe that the tape is attracted to the metal sphere. Which of the following statements could be true. List all that apply. (1) Electrons from the sphere moved into the salt water on your skin, where they reacted with sodium ions. (2) The excess negative charge from the sphere spread out all over your body. (3) Chloride ions from the salt water on your hand moved onto the sphere. (4) Sodium ions from the salt water on your hand moved onto the sphere. (5) Electrons from your hand moved onto the sphere. (6) Electrons from the sphere traveled through your body into the Earth. (7) After you touched it, the metal sphere was very nearly neutral.
Physics
1 answer:
hichkok12 [17]2 years ago
5 0

Answer:

(2) The excess negative charge from the sphere spread out all over your body.

(7) After you touched it, the metal sphere was very nearly neutral.

Explanation:

Plastic pen repels magic tape so magic tape is also  negatively charged . Further , magic tape repels small metal sphere that means small sphere also is negatively charged.

Now when small sphere is touched by a man insulated from ground , the charge is distributed between man and small sphere according to their capacitance .

Since human body will have greater capacitance ,it will acquire larger share of charge . Sphere being of very small size will retain very less charge and it will become almost neutral . Hence it will be   attracted by  charged tape .

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Static electricity occurs because_____________ are relatively easy to scrape off atoms ...?
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3 years ago
You prepare tea with 0.250 kg of water at 85.0 ºC and let it cool down to room temperature (20.0 ºC) before drinking it. Essenti
vladimir2022 [97]

Answer:

232 J/K

Explanation:

The amount of heat gained by the air = the amount of heat lost by the tea.

q_air = -q_tea

q = -mCΔT

q = -(0.250 kg) (4184 J/kg/ºC) (20.0ºC − 85.0ºC)

q = 68,000 J

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dS = dQ/T

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5 0
2 years ago
A transformer has a primary coil with 106 turns and a secondary coil of 340 turns. The AC voltage across the primary coil has a
UkoKoshka [18]

To solve this problem it is necessary to apply the concepts related to transformers, that is to say passive electrical device that transfers electrical energy from one electrical circuit to one or more circuits.

From the mathematical definition we have that the relationship between the voltage of the first coil and the second coil is proportional to the number of loops of the first and second loop, that is:

\frac{V_s}{V_p} = \frac{N_s}{N_p}

Where

V_p =  input voltage on the primary coil.

V_s=input voltage on the secondary coil.

N_p=  number of turns of wire on the primary coil.

N_s = number of turns of wire on the secondary  coil.

Replacing our values we have:

V_p = 128V

N_p = 106

N_s = 340

Replacing,

\frac{V_s}{128} = \frac{340}{106}

V_s = 410.56V

From the same relations of number of turns and the voltage of the first and second coil we also have the relation of electricity and voltage whereby:

V_s I_s = V_p I_p

Where

I_p= Current Primary Coil

I_s = Current secundary Coil

Therefore:

I_s = \frac{V_p I_p}{V_s}

I_s = \frac{(128)(6)}{410.56}

I_s = 1.87 A

Therefore the maximum values for the secondary coil of the voltage is 410.56V and Current is 1.87A

5 0
3 years ago
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