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Jlenok [28]
3 years ago
15

You observe that a negatively charged plastic pen repels a charged piece of magic tape. You then observe that the same piece of

tape is repelled when brought near a small metal sphere. You are wearing rubber soled shoes, and you touch the metal sphere with your hand. After you touch the metal sphere, you observe that the tape is attracted to the metal sphere. Which of the following statements could be true. List all that apply. (1) Electrons from the sphere moved into the salt water on your skin, where they reacted with sodium ions. (2) The excess negative charge from the sphere spread out all over your body. (3) Chloride ions from the salt water on your hand moved onto the sphere. (4) Sodium ions from the salt water on your hand moved onto the sphere. (5) Electrons from your hand moved onto the sphere. (6) Electrons from the sphere traveled through your body into the Earth. (7) After you touched it, the metal sphere was very nearly neutral.
Physics
1 answer:
hichkok12 [17]3 years ago
5 0

Answer:

(2) The excess negative charge from the sphere spread out all over your body.

(7) After you touched it, the metal sphere was very nearly neutral.

Explanation:

Plastic pen repels magic tape so magic tape is also  negatively charged . Further , magic tape repels small metal sphere that means small sphere also is negatively charged.

Now when small sphere is touched by a man insulated from ground , the charge is distributed between man and small sphere according to their capacitance .

Since human body will have greater capacitance ,it will acquire larger share of charge . Sphere being of very small size will retain very less charge and it will become almost neutral . Hence it will be   attracted by  charged tape .

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Ugo [173]
The temperature inside the copper rod varies linearly with the distance from the hot end of the rod. This means that we can find the temperature at 23 cm (let's call it 'point A') from the cool end by solving a linear proportion.

The temperature difference between the two ends of the rod is
\Delta T = 105^{\circ}-21^{\circ} = 84^{\circ}
and this corresponds to a length of 81 cm. Therefore, we can write:
84^{\circ}:81~cm = x:23~cm
from which we find
x=23.8~^{\circ}
This is not the final answer actually; this is the temperature difference between the cool end and point A. So, the temperature at point A is
T_A = 21^{\circ}+x=44.8^{\circ}
7 0
3 years ago
Can someone help me a bit on this? Will mark brainliest. ( no physical science option soooo)
Advocard [28]

Answer:

When a light wave goes through a slit, it is diffracted, which means the slit opening acts as a new source of waves. How much a light wave diffracts<em> (how much it fans out)</em> depends on the wavelength of the incident light. The wavelength must be larger than the width of the slit for the maximum diffraction. Thus, for a given slit, red light, because it has a longer wavelength, diffracts more than the blue light.

The corresponding relation for diffraction is

d sin(\theta) \approx \lambda,

where \lambda is the wavelength of light, d is the slit width, and \theta is the diffraction angle.

From this relation we clearly see that the diffraction angle \theta is directly proportional to the wavelength  \lambda of light—longer the wavelength larger the diffraction angle.

7 0
3 years ago
A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac
Lemur [1.5K]

Answer:

a)   v = 0.9167 m / s,  b)  A = 0.350 m,  c)  v = 0.9167 m / s, d)  A = 0.250 m

Explanation:

a) to find the velocity of the wave let us use the relation

          v = λ f

the wavelength is the length that is needed for a complete wave, in this case x = 5.50 m corresponds to a wavelength

           λ = x

           λ = x

the period is the time for the wave to repeat itself, in this case t = 3.00 s corresponds to half a period

          T / 2 = t

           T = 2t

period and frequency are related

           f = 1 / T

           f = 1 / 2t

we substitute

           v = x / 2t

           v = 5.50 / 2 3

           v = 0.9167 m / s

b) the amplitude is the distance from a maximum to zero

          2A = y

           A = y / 2

           A = 0.700 / 2

           A = 0.350 m

c) The horizontal speed of the traveling wave (waves) is independent of the vertical oscillation of the particles, therefore the speed is the same

      v = 0.9167 m / s

d) the amplitude is

           A = 0.500 / 2

           A = 0.250 m

4 0
2 years ago
A student fills a tank of radius r with water to a height of h1 and pokes a small, 1.0 cm diameter hole at a distance h2 from th
Alik [6]

when a hole is made at the bottom of the container then water will flow out of it

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By Bernoulli's equation we can write

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Now by equation of continuity

A_1v_1 = A_2v_2

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from above equation we can say that speed at the top layer is almost negligible.

v_1 = 0

now again by equation of continuity

\rho g h = \frac{1}{2} \rho v^2

v = \sqrt{2 g h}

here we have

h = h_1 - h_2

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now speed is given by

v = \sqrt{2* 9.8 * 0.47}

v = 3.03 m/s

7 0
3 years ago
What is the frequency of an x- ray if the wavelength is 4.5 E - 10m?
AnnZ [28]
V (speed) = F (frequency) x Wavelength
If we rearrange the formula, making frequency the subject;
F (frequency) = Speed ÷ Wavelength
F = 300,000 m\s x 4.5 e -10m
F = 0.08810409956 Hz
4 0
3 years ago
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