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GalinKa [24]
4 years ago
7

An astronaut is being tested in a centrifuge. The centrifuge has a radius R and, in starting, rotates according to θ = tn, where

t is in seconds, θ is in radians, and n is a positive integer. Find expressions for the the magnitudes of the astronaut's (a) angular velocity, (b) linear velocity, (c) tangential acceleration, and (d) radial acceleration at a general time t, in terms of the variables given.
Physics
1 answer:
Igoryamba4 years ago
4 0

Answer:

a) ω=n

b) V = R*n

c) a = 0

d) ar = R*n^2

Explanation:

Angular velocity is given by the derivative of θ:

ω = n

Linear Velocity will be:

V = ω*R = n*R

Tangential acceleration will be the derivative of the linear velocity. Since velovity is constant:

a = 0

Radial acceleration is given by:

ar = V^2/R = (R*n)^2/R=R*n^2

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How much energy is stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800
ozzi

Answer:

The energy stored in the solenoid is 7.078 x 10⁻⁵ J

Explanation:

Given;

diameter of the solenoid, d = 2.80 cm

radius of the solenoid, r = d/2 = 1.4 cm

length of the solenoid, L = 14 cm = 0.14 m

number of turns, N = 200 turns

current in the solenoid, I = 0.8 A

The cross sectional area of the solenoid is given as;

A = \pi r^2\\\\A = \pi (0.014)^2\\\\A = 6.16*10^{-4} \ m^2

The inductance of the solenoid is given by;

L = \frac{\mu_0 N^2A}{l} \\\\L =  \frac{(4\pi*10^{-7})(200^2)(6.16*10^{-4})}{0.14}\\\\L = 2.212*10^{-4} \ H

The energy stored in the solenoid is given by;

E = ¹/₂LI²

E = ¹/₂(2.212 x 10⁻⁴)(0.8)²

E = 7.078 x 10⁻⁵ J

Therefore, the energy stored in the solenoid is 7.078 x 10⁻⁵ J

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