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GalinKa [24]
3 years ago
7

An astronaut is being tested in a centrifuge. The centrifuge has a radius R and, in starting, rotates according to θ = tn, where

t is in seconds, θ is in radians, and n is a positive integer. Find expressions for the the magnitudes of the astronaut's (a) angular velocity, (b) linear velocity, (c) tangential acceleration, and (d) radial acceleration at a general time t, in terms of the variables given.
Physics
1 answer:
Igoryamba3 years ago
4 0

Answer:

a) ω=n

b) V = R*n

c) a = 0

d) ar = R*n^2

Explanation:

Angular velocity is given by the derivative of θ:

ω = n

Linear Velocity will be:

V = ω*R = n*R

Tangential acceleration will be the derivative of the linear velocity. Since velovity is constant:

a = 0

Radial acceleration is given by:

ar = V^2/R = (R*n)^2/R=R*n^2

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In the earth-moon system the moon orbits the earth. What is the "centripetal" force causing the moon to stay in orbit around the
gavmur [86]

The centripetal force is the gravitational force of attraction between the Earth and the Moon.

Also, the gravitational force of attraction between the Earth and the Sun is the centripetal force that causes the Earth to stay in orbit around the Sun.

Also, the gravitational force of attraction between a TV satellite, a weather satellite, or a GPS satellite and the Earth is the centripetal force that causes each satellite to stay in orbit around the Earth.

4 0
3 years ago
Who has greater displacement, an astronaut who has just completed an orbit of the earth or you when you have just traveled from
Arte-miy333 [17]

Answer:

Explanation:

This is going to sound like an absurd answer, but sometimes physics can be a little strange.

This answer is weird because of the definition of displacement. It means the distance from the starting point to the ending point, disregarding what happened in between. The point is that the astronaut is at the starting point of his orbit. By definition the starting and ending points are the same. His displacement is 0.

So the answer is you have the greater displacement when you walked one way to school.  The starting point and the ending point are different. You have gone further.

However just to make things a little nasty, when you walk home again, your displacement will be the same as the astronaut's -- 0 meters because you will be right back where you started from.

7 0
3 years ago
The parallel axis theorem relates Icm, the moment of inertia of an object about an axis passing through its center of mass, to I
erma4kov [3.2K]

Answer:

Part a)

I_{end} = \frac{mL^2}{3}

Part b)

I_{edge} = \frac{2ma^2}{3}

Explanation:

As we know that by parallel axis theorem we will have

I_p = I_{cm} + Md^2

Part a)

here we know that for a stick the moment of inertia for an axis passing through its COM is given as

I = \frac{mL^2}{12}

now if we need to find the inertia from its end then we will have

I_{end} = I_{cm} + Md^2

I_{end} = \frac{mL^2}{12} + m(\frac{L}{2})^2

I_{end} = \frac{mL^2}{3}

Part b)

here we know that for a cube the moment of inertia for an axis passing through its COM is given as

I = \frac{ma^2}{6}

now if we need to find the inertia about an axis passing through its edge

I_{edge} = I_{cm} + Md^2

I_{edge} = \frac{ma^2}{6} + m(\frac{a}{\sqrt2})^2

I_{edge} = \frac{2ma^2}{3}

7 0
3 years ago
How might you use a rope and pulley to move a wagon up a ramp?
sleet_krkn [62]
You could attach the pulley to a secure object on the top of the ramp, and crank the pulley to bring the wagon up said ramp into a loading bay perhaps, or a track. 

Hope I helped. 
7 0
3 years ago
a golf ball is hit with a velocity of 30.0 m/s at an angle of 25 degrees about the horizontal. how long is the ball in the air a
Pie
Ok so use trigonometry to work out the vertical component of velocity.

sin(25) =opp/hyp
rearrange to:
30*sin(25) which equals 12.67ms^-1

now use SUVAT to get the time of flight from the vertical component,

V=U+at

Where V is velocity, U is the initial velocity, a is acceleration due to gravity or g. and t is the time.

rearranges to t= (V+u)/a

plug in some numbers and do some maths and we get 2.583s

this is the total air time of the golf ball.

now we can use Pythagoras to get the horizontal component of velocity.

30^2-12.67^2= 739.29
sqrt739.29 = 27.19ms^-1

and finally speed = distance/time

so--- 27.19ms^-1*2.583s= 70.24m

The ball makes it to the green, and the air time is 2.58s 
4 0
3 years ago
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