Answer:
a) 0.25m
b) 5 m/s
Explanation:
When the spring is compressed both boxes are moving with the same velocity, so applying the principle of linear momentum conservation:

Now applying the principle of energy conservation:

We got that the maximum compression is 0.25m.
Answer:
331.7m/s
Explanation:
Given parameters:
Initial velocity = 100m/s
Acceleration = 50m/s²
Distance = 1km = 1000m
Unknown:
Final velocity = ?
Solution:
To solve this problem, we have to apply the right motion equation shown below;
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance
Now insert the parameters and solve;
v² = 100² + (2 x 50 x 1000)
v² = 110000
v = √110000 = 331.7m/s
Answer:
See solution with all the conditions considered. A gaseous mixture of A and B for which species A is chemically consumed at the catalytic surface.
The total pore reaction rate is stated below and it can be inferred by applying the bellow analogy.
Answer:
C) С
Explanation:
'C' and 'E' are compressions.
'A' and 'D' are rarefactions.
have a good Day!