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3 years ago

Transverse waves are generally stronger than longitudinal waves. True or False ?

Physics

1 answer:

kondaur [170]3 years ago

8 0

False
If all other factors, such as medium, are kept the same, longitudinal waves tend to be stronger.

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Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to thenext handhold. A 9.3kggibbon has

Mumz [18]

Upward force provided by the branch is 260 N

<u>Explanation:</u>

Given -

Mass of Gibbon, m = 9.3 kg

Length of the branch, r = 0.6 m

Speed of the movement, v = 3.3 m/s

Upward force, T = ?

The tension force in the rod must be greater than the weight at the bottom of the swing in order to provide an upward centripetal acceleration.

Therefore,

F net = T - mg

F net = ma = mv²/r

Thus,

T = mv²/r + mg

T = m ( v²/r + g)

T = 9.3 [ ( 3.3)² / 0.6 + 9.8]

T = 259.9 N ≈ 260 N

Therefore, upward force provided by the branch is 260 N

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3 years ago

A laser beam of unknown wavelength passes through adiffraction grating having 5510 lines/cm after striking itperpendicularly. Ta

Ivahew [28]

Answer:

Explanation:

distance between two slit d = $\frac{1 \times 10^{-2}}{5510}$

d = 18.15 x 10⁻⁷ m

Let wave length of light λ

formula for position of first pair of bright spot

Tanθ = λ / d , λ is wave length of light and d is distance between two slit .

Tan 15.4 = $\frac{\lambda}{18.15\times10^{-7}}$

λ = Tan 15.4 x 18.15 x 10⁻⁷

=5 x 10⁻⁷ m

If θ be the position of next bright spot

Tanθ = 2 λ / d

= $\frac{2 \times\ 5\times\ 10^ {-7}}{18.15\times10^{-7}}$

= $\frac{2\times5}{18.5}$

θ = 28.4 degree .

7 0

3 years ago

PLEASE PLEASE HELP<br> (Picture)

atroni [7]

Answer:

light slows it down

Explanation:

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3 years ago

A thin copper rod 1.0 m long has a mass of 0.050 kg and is in a magnetic field of 0.10 t. What minimum current in the rod is nee

slamgirl [31]

Answer:

$i = 4.9 A$

Explanation:

Force on a current carrying rod due to magnetic field is given as

$F = iLB$

here we know that

$i =$ current in the rod

$B = 0.10 T$

$L = 1.0 m$

now magnetic force is balanced by the weight of the rod

so we will have

$iLB = mg$

$i(1.0)(0.10) = 0.05 \times 9.8$

$i = 4.9 A$

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3 years ago

What is the changing of the position of an object relative to a point of reference

Bond [772]

The displacement ........................

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3 years ago