Answer:
This formula R =ρL/A
Where R = resistance of wire, ρ = resistivity of the wire and A = area of the wire. Shows there is an inverse relationship between Resistance and Area of the wire.
Explanation:
A simple way to explain the physics behind such an electrical code is to compare the flow of current through wires to the flow of water through pipes, they are similar in any respect. The resistance to the flow of current in an electric circuit is similar to the frictional experienced by water when flowing through water pipes. Just as water will flow easily with little resistance through a water pipe with the larger cross-sectional area than one with a smaller cross-sectional area, in the same way, wires with larger cross-sectional area will allow the flow of larger amount of current compared to wires with smaller cross-sectional area assuming all other variables are the same.
From the formula R =ρL/A
Where R = resistance of wire, ρ = resistivity of the wire and A = area of the wire
We can see that the resistance and area of the wire have an inverse relationship. An increase in the area of the wire will lead to a decrease in the resistance of the wire.
It is the smallest planet with a bluish color that can probably make it look like a comet
<span>A wave with a large amplitude has a lot of a.vibration b.speed <u> c.energy</u></span>
<h2>
Answer:</h2>
D. (1m, 0.5m)
<h2>
Explanation:</h2>
The center of mass (or center of gravity) of a system of particles is the point where the weight acts when the individual particles are replaced by a single particle of equivalent mass. For the three masses, the coordinates of the center of mass C(x, y) is given by;
x = (m₁x₁ + m₂x₂ + m₃x₃) / M ----------------(i)
y = (m₁y₁ + m₂y₂ + m₃y₃) / M ----------------(ii)
Where;
M = sum of the masses
m₁ and x₁ = mass and position of first mass in the x direction.
m₂ and x₂ = mass and position of second mass in the x direction.
m₃ and x₃ = mass and position of third mass in the x direction.
y₁ , y₂ and y₃ = positions of the first, second and third masses respectively in the y direction.
From the question;
m₁ = 6kg
m₂ = 4kg
m₃ = 2kg
x₁ = 0m
x₂ = 3m
x₃ = 0m
y₁ = 0m
y₂ = 0m
y₃ = 3m
M = m₁ + m₂ + m₃ = 6 + 4 + 2 = 12kg
Substitute these values into equations (i) and (ii) as follows;
x = ((6x0) + (4x3) + (2x0)) / 12
x = 12 / 12
x = 1 m
y = (6x0) + (4x0) + (2x3)) / 12
y = 6 / 12
y = 0.5m
Therefore, the center of mass of the system is at (1m, 0.5m)
Answer:
The wheelbarrow's wheel and axle help the wheelbarrow to move without friction thus making it easier to push or pull. That's why it will be easier to lift a load in wheel barrow of the load is transferred towards the wheel.
