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tiny-mole [99]
2 years ago
9

20.8 grams of ethanol (CH3CH2OH) was burned in a calorimeter containing 200.0 grams of water. If the

Chemistry
1 answer:
Nata [24]2 years ago
5 0

Answer:

Csmall pan=18,140J50.0°C=363J/°C

Explanation:

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If I want to accelerate a mass of 3 kg at 5 m/s2 then how much force should I apply?
Stolb23 [73]

<u>Answer:</u> The force that must be applied is 15 N.

<u>Explanation:</u>

Force exerted on the object is defined as the product of mass of the object and the acceleration of the object.

Mathematically,

F=m\times a

where,

F = force exerted = ?

m = mass of the object = 3 kg

a = acceleration of the object = 5m/s^2

Putting values in above equation, we get:

F=3kg\times 5m/s^2=15N

Hence, the force that must be applied is 15 N.

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3 years ago
The diagram shows a model of the nitrogen cycle. which role do plants play in the nitrogen cycle?
kenny6666 [7]

Answer

D

Explanation:

They take up usable forms of nitrogen found in soil

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2 years ago
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What is a mixture,what is a solution
Masteriza [31]
If it’s chemistry then In chemistry, a solution is a special type of homogeneous mixture composed of two or more substances. In such a mixture, a solute is a substance dissolved in another substance, known as a solvent.
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3 years ago
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Beginning
Bas_tet [7]

Answer:

yeah it is

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what rhe ebenja

4 0
2 years ago
A sample of propane(c3h8)has 3.84x10^24 H atoms.
deff fn [24]

Answer:

A) 14. 25 × 10²³ Carbon atoms

B) 34.72 grams

Explanation:

1 molecule of Propane has 3 atoms of Carbon and 8 atoms of Hydrogen.

The sample has 3.84 × 10²⁴ H atoms.

If 8 atoms of Hydrogrn are present in 1 molecule of propane.

3.84 × 10²⁴ H atoms are present in

\mathfrak{ \frac{3.8 }{8} \times 10 ^{24}}

<u>= 4.75 × 10²³ molecules of Propane</u>.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

No. of Carbon atoms in 1 molecule of propane = 3

=> C atoms in 4.75× 10²³ molecules of Propane = 3 × 4.75 × 10²³

<u>= 14.25 × 10²³ </u>

<u>________________________________________</u>

<u>Gram</u><u> </u><u>Molecular</u><u> </u><u>Mass</u><u> </u><u>of</u><u> </u><u>Propane</u><u>(</u><u>C3H8</u><u>)</u>

= 3 × 12 + 8 × 1

= 36 + 8

= 44 g

1 mole of propane weighs 44g and has 6.02× 10²³ molecules of Propane.

=> 6.02 × 10²³ molecules of Propane weigh = 44 g

=> 4. 75 × 10²³ molecules of Propane weigh =

\mathsf{ \frac{44 }{6.02 \times  {10}^{23} } \times 4.75 \times  {10}^{23}  }

\mathsf{  = \frac{44 }{6.02 \times   \cancel{{10}^{23} }} \times 4.75 \times \cancel{ {10}^{23}}  }

\mathsf{  = \frac{44 }{6.02 } \times 4.75   }

<u>= 34.72 g</u>

8 0
2 years ago
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