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d1i1m1o1n [39]
3 years ago
12

Why can friction make observing Newton's first law of motion difficult?

Physics
1 answer:
Kamila [148]3 years ago
6 0
The law says things travel in a straight line at constant speed unless acted upon by a force.  But friction is a force but it can't be seen easily other than its effect, which is to bring the object to rest in seeming violation of the 1st law.
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Please answer my question!,
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Answer:

Hope this helps! Mark as brainliest if liked thanks!

Explanation:

Your reasoning that the shadow is the shortest at mid-day is spot-on!

The wording of the question is the key to the answer. It says that the measurements were made in Summer. So this means that British Summer Time (BST) is being applied. BST is one hour ahead of Greenwich Mean Time and so what looks like 1pm is really 12 noon.

The safest sort of answer is to say that the shadow is shortest when the sun is at its highest point, and in this particular question that is at 1 pm because it is BST.

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Which of the following is a<br> fossil fuel?<br> A. Coal<br> B. Wind energy<br> C. Biomass energy
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is the correct answer

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A mirror forms an erect image 40cm from the object and one third its height where must the mirror be situated ​
iragen [17]

The mirror is located 30 cm from the object

Explanation:

To solve the problem, we can use the magnification equation, which states that:

M=\frac{y'}{y}=-\frac{q}{p}

where

M is the magnification

y' is the size of the image

y is the size of the object

q is the distance of the image  from the mirror

p is the distance of the object from the mirror

In this problem, we notice that the image formed by the mirror is erect and diminished: this means that this is a convex mirror, so the image is virtual, and this means that the image and the object are located on opposite sides of the mirror. Therefore,

p-q=40 cm (distance of the image from the object is 40 cm, but since the image is virtual, q is the negative)

The size of the image is 1/3 that of the object, so

y'=\frac{1}{3}y

Solving the equation for p, we find the distance between the object and the mirror:

\frac{y'}{y}=-\frac{p-40}{p}\\\\p=\frac{40}{1+\frac{y'}{y}}=\frac{40}{4/3}=30 cm

So, the mirror is 30 cm from the object.

#LearnwithBrainly

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Studentka2010 [4]

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did u get it?

Explanation:

frfr

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