Answer:
The answer would be the last option (the one with the arrow pointing sideways)
Explanation:
The arrow lost it's acceleration and is starting to go downwards but it isn't a straight slope down
Answer:
The magnitude of the lift force L = 92.12 kN
The required angle is ≅ 16.35°
Explanation:
From the given information:
mass of the airplane = 9010 kg
radius of the airplane R = 9.77 mi
period T = 0.129 hours = (0.129 × 3600) secs
= 464.4 secs
The angular speed can be determined by using the expression:
ω = 2π / T
ω = 2 π/ 464.4
ω = 0.01353 rad/sec
The direction 

θ = 16.35°
The magnitude of the lift force L = mg ÷ Cos(θ)
L = (9010 × 9.81) ÷ Cos(16.35)
L = 88388.1 ÷ 0.9596
L = 92109.32 N
L = 92.12 kN
The biological process that directly converts energy from the Sun into chemical energy would be Photosynthesis. It is a process carried out by autotrophic organisms which are predominantly plants and other photosynthetic bacteria.
There are two possibilities for this question:
1- The shopping cart is at rest (not moving):
In this case:
∑Forces = 0
Force exerted by Jim + Force exerted by cart = 0
2 + Force exerted by cart = 0
Force exerted by cart = -2
2- The cart is moving as a result of a net force "m":
In this case:
∑Forces = m
Force exerted by Jim + Force exerted by cart = m
Force exerted by cart = m-2
To solve this problem it is necessary to apply the concepts related to acceleration due to gravity, as well as Newton's second law that describes the weight based on its mass and the acceleration of the celestial body on which it depends.
In other words the acceleration can be described as

Where
G = Gravitational Universal Constant
M = Mass of Earth
r = Radius of Earth
This equation can be differentiated with respect to the radius of change, that is


At the same time since Newton's second law we know that:

Where,
m = mass
a =Acceleration
From the previous value given for acceleration we have to

Finally to find the change in weight it is necessary to differentiate the Force with respect to the acceleration, then:




But we know that the total weight (F_W) is equivalent to 600N, and that the change during each mile in kilometers is 1.6km or 1600m therefore:


Therefore there is a weight loss of 0.3N every kilometer.