Answer:
17.4 cm
Explanation:
Power of lens = +1.75 diopters
Focal length of lens
![f=\frac{100}{1.75}=\frac{400}{7}](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B100%7D%7B1.75%7D%3D%5Cfrac%7B400%7D%7B7%7D)
This is a convex lens as focal the diopter given is positive which makes the focal length positive. Image distance will be negative.
v = -25
![\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\\\Rightarrow \frac{1}{-25}-\frac{1}{u}=\frac{1}{\frac{400}{7}}\\\Rightarrow -\frac{1}{u}=\frac{7}{400}+\frac{1}{25}\\\Rightarrow \frac{1}{u}=-\frac{7}{400}-\frac{1}{25}\\\Rightarrow \frac{1}{u}=-0.0575\\\Rightarrow u=-17.4\ cm](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bv%7D-%5Cfrac%7B1%7D%7Bu%7D%3D%5Cfrac%7B1%7D%7Bf%7D%5C%5C%5CRightarrow%20%5Cfrac%7B1%7D%7B-25%7D-%5Cfrac%7B1%7D%7Bu%7D%3D%5Cfrac%7B1%7D%7B%5Cfrac%7B400%7D%7B7%7D%7D%5C%5C%5CRightarrow%20-%5Cfrac%7B1%7D%7Bu%7D%3D%5Cfrac%7B7%7D%7B400%7D%2B%5Cfrac%7B1%7D%7B25%7D%5C%5C%5CRightarrow%20%5Cfrac%7B1%7D%7Bu%7D%3D-%5Cfrac%7B7%7D%7B400%7D-%5Cfrac%7B1%7D%7B25%7D%5C%5C%5CRightarrow%20%5Cfrac%7B1%7D%7Bu%7D%3D-0.0575%5C%5C%5CRightarrow%20u%3D-17.4%5C%20cm)
∴ The new near point is 17.4 cm
Answer:
the answer is C
Explanation:
The car, first is at rest and if you don't accelerate it won't move. When to hit the gas it will accelerate from rest
Hey JayDilla, I get 1/3. Here's how:
Kinetic energy due to linear motion is:
![E_{linear}= \frac{1}{2}mv^2](https://tex.z-dn.net/?f=E_%7Blinear%7D%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20)
where
![v=r \omega](https://tex.z-dn.net/?f=v%3Dr%20%5Comega)
giving
![E_{linear}= \frac{1}{2}mr^2 \omega ^2](https://tex.z-dn.net/?f=E_%7Blinear%7D%3D%20%5Cfrac%7B1%7D%7B2%7Dmr%5E2%20%5Comega%20%5E2)
The rotational part requires the moment of inertia of a solid cylinder
![I_{cyl} = \frac{1}{2}mr^2](https://tex.z-dn.net/?f=I_%7Bcyl%7D%20%3D%20%20%5Cfrac%7B1%7D%7B2%7Dmr%5E2%20)
Then the rotational kinetic energy is
![E_{rot}= \frac{1}{2}I \omega ^2= \frac{1}{4}mr^2 \omega ^2](https://tex.z-dn.net/?f=E_%7Brot%7D%3D%20%5Cfrac%7B1%7D%7B2%7DI%20%5Comega%20%5E2%3D%20%5Cfrac%7B1%7D%7B4%7Dmr%5E2%20%5Comega%20%5E2)
Adding the two types of energy and factoring out common terms gives
![\frac{1}{2}mr^2 \omega ^2(1+ \frac{1}{2})](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7Dmr%5E2%20%5Comega%20%5E2%281%2B%20%5Cfrac%7B1%7D%7B2%7D%29%20%20)
Here the "1" in the parenthesis is due to linear motion and the "1/2" is due to the rotational part. Since this gives a total of 3/2 altogether, and the rotational part is due to a third of this (1/2), I say it's 1/3.
Answer:
a) f=0.1 Hz ; b) T=10s
c)λ= 36m
d)v=3.6m/s
e)amplitude, cannot be determined
Explanation:
Complete question is:
Determine, if possible, the wave's (a) frequency, (b) period, (c) wavelength, (d) speed, and (e) amplitude.
Given:
number of wave crests 'n'= 5
pass in a time't' 54.0s
distance between two successive crests 'd'= 36m
a) Frequency of the waves 'f' can be determined by dividing number of wave crests with time, so we have
f=n/t
f= 5/ 54 => 0.1Hz
b)The time period of wave 'T' is the reciprocal of the frequency
therefore,
T=1/f
T=1/0.1
T=10 sec.
c)wavelength'λ' is the distance between two successive crests i.e 36m
Therefore, λ= 36m
d) speed of the wave 'v' can be determined by the product of frequency and wavelength
v= fλ => 0.1 x 36
v=3.6m/s
e) For amplitude, no data is given in this question. So, it cannot be determined.