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schepotkina [342]
4 years ago
7

What keeps the particles of a liquid from spreading out to fill an entire container in the same way that gas particles do?

Physics
2 answers:
Sonbull [250]4 years ago
7 0

b. the forces of attraction among them limit their motion.


frutty [35]4 years ago
6 0

Answer:

b. the forces of attraction among them limit their motion.

Explanation:

In solids, the particles are tightly packed. The solid has fixed shape and volume.There is strong inter-particle force of attraction which prevents the motion  of particles in solids. Thus, the particles in solids can vibrate about their fixed position.  Liquids have fixed volume but not shape. Gases don't  have fixed shape and volume. The particles of liquid do not spread out like gases. This is because of the inter particle attraction which prevents them from moving far away. In gases, the inter-particle distance is large and thus, particles have weak force of attraction.

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2 (a) A plane from airport A flies 280 km to the east to airport B. The plane then travelled north to airport C, 190 km away. (i
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Answer:

See below

Explanation:

See attached diagram

280 km   east then 190 km north

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d^2 = 280^2 + 190^2

d = 338.4 km

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2 years ago
Consider a variety of colors of visible light (say 400 nm to 700 nm) falling onto a pair of slits.
babymother [125]

Answer:

Explanation:

The relationship between angle and wavelength for maxima and minima in Young's double slit experiment is given by

For constructive interference

d\sin \theta =m\lambda

For Destructive interference

d\sin \theta =(m+\frac{1}{2})\lambda

where \lambda =wavelength

d=slit\ width

m=order of maxima and minima

for second order maxima i.e. m=2

For smallest separation taking \lambda =400 nm, \theta =90^{\circ}

d\sin 90=2\times 400\times 10^{-9}

d=0.8\times 10^{-6}

d=0.8\mu m

   

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3 years ago
In 3-5 sentences, explain the difference between mass and weight and summarize how mass and weight are related to gravitational
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A basketball player jumps straight up for a ball. To do this, he lowers his body 0.310 m and then accelerates through this dista
Nastasia [14]

Answer:A)u =4.295m/s  , B)a = 29.746m/s²   C) F=3,153N

Explanation:

Using the kinematic expression  

v² = u² - 2as

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u = initial velocity

v = final velocity

s = distance

g = acceleration due to gravity .

Given that he reaches a height of 0.940 m above the floor,

the final velocity  = 0

Here, acceleration due to gravity is acting in  opposite the initial direction of motion. So, a=-9.81 m/s.

v² = u² + 2as

0² - u² = 2 (- 9.81) × 0.940

- u² = 2 × - 9.81 × 0.920

- u² = -18.4428

cancelling the minus in both sides , we have that  

u² = 18.4428

u = √18.4428

u =4.295m/s

(b) His acceleration (in m/s2) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.310 m. m/s2

Using v² = u² + 2as

where u = initial speed of basketball player before lengthening = 0 m/s,

v = final speed of basketball player after lengthening =  4.295m/s,

a = acceleration while  straightening his legs

s = distance moved during lengthening = 0.310m

v² = u² + 2as  

 a = (v² - u²)/2s

a = (4.29m/s)² - (0 m/s)²)/(2 × 0.310m)

a = (18.4428 m²/s² - 0 m²/s²)/(0.62 m)

a = (18.4428 m²/s²/(0.62 m)

a = 29.746m/s²

c) The force (in N) he exerts on the floor to do this, given that his mass is 106 kg. N

Force= mass x acceleration.

F = 106 kg X 29.746m/s²

 F = 3,153.076 rounded to  3,153N

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