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schepotkina [342]
3 years ago
7

What keeps the particles of a liquid from spreading out to fill an entire container in the same way that gas particles do?

Physics
2 answers:
Sonbull [250]3 years ago
7 0

b. the forces of attraction among them limit their motion.


frutty [35]3 years ago
6 0

Answer:

b. the forces of attraction among them limit their motion.

Explanation:

In solids, the particles are tightly packed. The solid has fixed shape and volume.There is strong inter-particle force of attraction which prevents the motion  of particles in solids. Thus, the particles in solids can vibrate about their fixed position.  Liquids have fixed volume but not shape. Gases don't  have fixed shape and volume. The particles of liquid do not spread out like gases. This is because of the inter particle attraction which prevents them from moving far away. In gases, the inter-particle distance is large and thus, particles have weak force of attraction.

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A company has been hired to perform environmental remediation on an area of marshland. What would they most likely do?
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Answer:

remove contamination; pollution ; test ground water and dirt .

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Your starship, the Aimless Wanderer,lands on the mysterious planet Mongo. As chief scientist-engineer,you make the following mea
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Answer:

a)  M = 4,997 10²⁰ kg ,  b)   T = 1.43 10³ s

Explanation:

a) This exercise should be solved in several parts, let's start by calculating the acceleration of gravity of this planet from kinematics

          v = v₀ - a t

As it indicates that there is no atmosphere, the friction force is zero and the initial and final velocity have the same module, but the opposite direction

         a = (v₀ - v) / t

         a = (15 - (-15)) /9.00 = 30/9

         a = 3.33 m / s²

Now we use Newton's second law where force is the force of universal attraction

          F = m a

         G m M / r² = m a

         M = a r² / G

Let's calculate

         M = 3.33 (1.00 10⁵)² / 6.67 10⁻¹¹

         M = 4,997 10²⁰ kg

b) The period of the ship's orbit

In this case we have a centripetal acceleration

The radius of the orbit is the radius of the plant plus the height of the ship from the surface

         R = R_{m} + h

         R = 1 10⁵ + 2.00 10⁴

         R = 12 10⁴ m

         F = m a

        G m M / R² = m a

Centripetal acceleration is

         a = v² / R

The orbit is circular therefore the velocity module is constant, so we can use the equation of uniform motion, where the distance is the length of the orbit, for a circle

        d = 2π R

        v = d / t

        v = 2π R / T

Let's replace

        G m M / R² = m (2π R / T)² / R

        G M = R³ 4π² / T²

        T² = 4π² R³ / G M

       T² = (4π² (12 10⁴)³ / (6.67 10⁻¹¹ 4,997 10²⁰)

       T² = 6.82 10¹⁶ / 3.33 10¹⁰

       T = √ (2,048 10⁶)

       T = 1.43 10³ s

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3 years ago
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Answer:

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Explanation:

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Answer:

Following are the solution to this question:

Explanation:

Law:

\to \theta= 180^{\circ}- 50^{\circ}- 25^{\circ}

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