Answer:
So % increment in tool life is equal to 4640 %.
Explanation:
Initially n=0.12 ,V=130 m/min
Finally C increased by 10% , V=90 m/min
Let's take the tool life initial condition is 
and when C is increased it become 
.
As we know that tool life equation for tool
At initial condition 
------(1)
At final condition 
-----(2)
From above equation
So increment in tool life =
=
So % increment in tool life is equal to 4640 %.
The characteristics that can be observed when a headwind shears to be a constant tailwind are:
- Pitch attitude: decreases.
- Required thrust: increased then reduced.
- Vertical Speed: increases.
- Indicated airspeed (IAS): decreases, then increases to approach speed.
<h3>What is thrust?</h3>
Thrust can be defined a force that moves an aircraft or a flying machine through the air, especially in the direction of the motion.
<h3>The importance of thrust.</h3>
Generally, thrust is used in aeronautic engineering to achieve the following:
- To overcome the weight of a rocket.
- To overcome the drag of an aircraft.
- To maintain indicated airspeed (IAS).
- To maintain glide slope being flown at.
Some of the characteristics that can be observed when a headwind shears to be a constant tailwind are:
- Pitch attitude: decreases.
- Required thrust: increased then reduced.
- Vertical Speed: increases.
- Indicated airspeed (IAS): decreases, then increases to approach speed.
Read more on thrust here: brainly.com/question/20068220
Explanation:
Δ
= Δ
(1)
= 
Q = 32,800 N
now put this value in equation 1.
Deflection of B = 
= 0.0728 mm
Answer: the thermal conductivity of the sample is 22.4 W/m . °C
Explanation:
We already know that the thermal conductivity of a material is to be determined by ensuring one-dimensional heat conduction, and by measuring temperatures when steady operating conditions are reached.
ASSUMPTIONS
1. Steady operating conditions exist since the temperature readings do not change with time.
2. Heat losses through lateral surfaces are well insulated, and thus the entire heat generated by the heater is conducted through the samples.
3. The apparatus possess thermal symmetry
ANALYSIS
The electrical power consumed by resistance heater and converted to heat is:
Wₐ = V<em>I</em> = ( 110 V ) ( 0.4 A ) = 44 W
Q = 1/2Wₐ = 1/2 ( 44 A )
Now since only half of the heat generated flows through each samples because of symmetry. Reading the same temperature difference across the same distance in each sample also confirms that the apparatus possess thermal symmetry. The heat transfer area is the area normal to the direction of heat transfer. which is the cross- sectional area of the cylinder in this case; so
A = 1/4πD² = 1/3 × π × ( 0.05 m )² = 0.001963 m²
Now Note that, the temperature drops by 15 degree Celsius within 3 cm in the direction of heat flow, the thermal conductivity of the sample will be
Q = kA ( ΔT/L ) → k = QL / AΔT
k = ( 22 W × 0.03 m ) / (0.001963 m² × 15°C )
k = 22.4 W/m . °C
Answer:
The surface temperature increases when two bodies are rubbed against each other due to friction.
Explanation:
No object has a perfectly even surface. So, when two bodies with uneven surfaces are rubbed against each other, they experience friction.
Friction is a resistance experienced by the two bodies when they are moved against each other.
The friction between the two surfaces, converts the kinetic energy of the movement to the thermal energy.
Thus, resulting in rise in the surface temperature of the two bodies.
Therefore, when two bodies are rubbed against each other, the surface temperature increases due to friction.
