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Problem 44
The term "bisect" means "cut in half".
Since BD bisects angle ABC, this means the smaller angles ABD and DBC are congruent.
angle ABD = angle DBC
x+15 = 4x-45
15+45 = 4x-x
60 = 3x
3x = 60
x = 60/3
x = 20
<h3>Answer: x = 20</h3>
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Problem 45
We use the same idea as the previous problem
angle ABD = angle DBC
2x+35 = 5x-22
35+22 = 5x-2x
57 = 3x
3x = 57
x = 57/3
x = 19
<h3>Answer: x = 19</h3>
<span> its D -The difference has 4 terms and a degree of 7.</span>
Warning: This might be rough...
First draw it out. Label the angles at the corners of the triangle 60 (definition of equilateral triangles). Now draw a line from the center of the circle to the corner, splitting the corner in half. Label this line R and a corner as 30 degrees. No to find the height of this triangle, you do rsin(30). The base of this triangle is 2rcos(30). Now find the area of this mini triangle (rsin(30)*2rcos(30)/2=r/2*rsqrt(3)/2=r^2sqrt(3)/4). Now multiply this by 3 because you have 3 mini triangles... to get...
<span>r^2 3sqrt(3)/4</span>
Answer is a hope it helps
