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katen-ka-za [31]
3 years ago
7

A 1.0-cm-diameter pipe widens to 2.0, then narrows to 0.5. Liquid flows through the first segment at a speed of 4.0. What is the

volume flow rate through the pipe?
Physics
1 answer:
uysha [10]3 years ago
3 0

Answer:

3.14 ×  10⁻⁴  m³  /s

Explanation:

The flow rate (Q) of a fluid is passing through different cross-sections remains of pipe always remains the same.

Q = Area x velocity

Given:

Diameters of 3 sections of the pipe are given as  

d1  =  1.0  cm,  d2  =  2.0  cm  and  d3  =  0.5  cm.

Speed in the first segment of the pipe is  

v1  =  4  m/s.

From the equation of continuity the flow rate through different cross-sections remains the same.

Flow  rate  =  Q  =  A1  v1  =  A2  v2  =  A3  v3.

Q = A1v1

   =π/4  d²1  v1  =  π/4  * 0.01² ×4.0 m³/s  =  3.14 ×  10⁻⁴  m³  /s

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Scientists might make a computer model of volcanic eruptions. What is the
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Answer:

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7 0
1 year ago
The potential difference between the plates of an air-filled parallel-plate capacitor with a plate separation of 4 cm is 51 V. W
Salsk061 [2.6K]

Answer:

Explanation:

Electric field between plates of a parallel plate capacitor is uniform .

In a uniform electric field , relation between electric field and potential gradient is as follows

electric field = potential gradient               [ E = - dV / dl ]

in the given case ,

dV = 51 V  ,

dl = 4 cm

=  4 x 10⁻² m

E = 51 /  4 x 10⁻²

= 12.75 x 10² V / m

= 1275 V / m

6 0
3 years ago
A bell is ringing inside of a sealed glass jar that is connected to a vacuum pump. Initially, the jar is filled with air. What d
Mila [183]

Answer:

See Explanation

Explanation:

Sound is a mechanical wave. A mechanical wave requires a material medium for propagation. This means that sound waves must be carried in air. If there are no air molecules, sound waves can not travel.

When air is gradually removed from the jar by the pump, the sound intensity from the bell gradually decreases owing to the fact that air which is the medium through which sound waves are propagated is gradually being removed from the jar.

4 0
3 years ago
Spaceship 1 and spaceship 2 have equal masses of 200 kg. Spaceship 1 has a speed of 0 m/s, and spaceship 2 has a speed of 10 m/s
m_a_m_a [10]

Answer:

2000 kg m/s

Explanation:

The momentum of an object is a vector quantity whose magnitude is given by

p=mv

where

m is the mass of the object

v is the velocity of the object

and its direction is the same as the velocity.

In this problem, we have:

- Spaceship 1 has

m = 200 kg (mass)

v = 0 m/s (zero velocity)

So its momentum is

p_1 =(200)(0)=0

- Spaceship 2 has

m = 200 kg (mass)

v = 10 m/s (velocity)

So its momentum is

p_2=(200)(10)=2000 kg m/s

Therefore, the combined momentum of the two spaceships is

p=p_1+p_2=0+2000=2000 kg m/s

3 0
3 years ago
Black widow (m=57000 g) shovels snow, holding the shovel at a 40 degree angle above the ground. If she uses a constant force of
Dima020 [189]

Answer:

She does a work of 689.44 J in the snow.

Explanation:

A force is said to do work when it alters the state of motion of a body. The work of the force on that body will be equivalent to the energy needed to move it.

In other words, Work is a form of energy transmission between bodies. In order to carry out work, a force must be exerted on a body and it must move.

The work is equal to the product of the force times the distance and the cosine of the angle that exists between the direction of the force and the direction that the moving point or object travels:

W= F*d* cos Ф

Work W is measured in joules (J), force is measured in newtons (N), and displacement in meters (m).

In this case:

  • F= 180 N
  • d=5 m
  • Ф= 40 degrees

Replacing:

W= 180 N*5 m* cos 40

Solving:

W= 689.44 J

<u><em>She does a work of 689.44 J in the snow.</em></u>

7 0
3 years ago
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