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anzhelika [568]
3 years ago
12

PLEASE help!!

Chemistry
1 answer:
Alina [70]3 years ago
5 0

Answer:

<h3>KBr + I- ---------> KI + Br-</h3>

Explanation:

Single Displacement reaction is a chemical Reaction in which one element in the salt is replaced with another element

for example,

A-B + C -------> A-C + B

electropositive replaces only electropositive elements from compound. same is true for electronegative element

in first reaction I being electro negative replaces Br from KBr so this is a single displacement reaction

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Answer:

Surface waves travel along the surface. There are two types of body waves: P-waves travel fastest and through solids, liquids, and gases; S-waves only travel through solids.

Explanation:

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3 years ago
If the fugacity of a pure component at the conditions of an ideal solution is 40 bar and its mole fraction is 0.4, what is its f
yaroslaw [1]

Answer : The fugacity in the solution is, 16 bar.

Explanation : Given,

Fugacity of a pure component = 40 bar

Mole fraction of component  = 0.4

Lewis-Randall rule : It states that in an ideal solution, the fugacity of a component is directly proportional to the mole fraction of the component in the solution.

Now we have to calculate the fugacity in the solution.

Formula used :

f_i=X_i\times f_i^o

where,

f_i = fugacity in the solution

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X_1 = mole fraction of component

Now put all the give values in the above formula, we get:

f_i=0.4\times 40\text{ bar}

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Therefore, the fugacity in the solution is, 16 bar.

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Enough of a monoprotic weak acid is dissolved in water to produce a 0.0144 0.0144 M solution. The pH of the resulting solution i
alexdok [17]

Answer:

The value of dissociation constant of the monoprotic acid is 1.099\times 10^{-3}.

Explanation:

The pH of the solution = 2.46

pH=-\log[H^+]

2.46=-\log[H^+]

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HA\rightleftharpoons H^++A^-

Initially

0.0144         0      0

At equilibrium

(0.0144-x)       x       x

The expression if an dissociation constant is given by :

K_a=\frac{[A^-][H^+]}{[HA]}

K_a=\frac{x\times x}{(0.0144-x)}

x=[H^+]=0.003467 M

K_a=\frac{0.003467 \times 0.003467 }{(0.0144-0.003467 )}

K_a=1.099\times 10^{-3}

The value of dissociation constant of the monoprotic acid is 1.099\times 10^{-3}.

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