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stellarik [79]
3 years ago
10

What speed would a fly with the mass of 0.55 g need in order to have the same kinetic energy as the automobile in the term 19

Physics
1 answer:
larisa86 [58]3 years ago
5 0

<u>The question does not provide enough information to complete the answer, so I'll assume the needed data to help you to solve your own problem</u>

Answer:

<em>The fly should need to move at 9,534.6 m/s to have the same kinetic energy as the automobile</em>

Explanation:

<u>Kinetic Energy </u>

Is the capacity of a body to do work due to its speed and is computed by

\displaystyle K=\frac{mv^2}{2}

We are not given enough data to compare the kinetic energy of the fly with that of the automobile. We'll assume the following characteristics:  

m_a=500\ kg

v_a=10\ m/s

So its kinetic energy is

\displaystyle K_a=\frac{(500)10^2}{2}

\displaystyle K_a=25,000\ J

The mass of the fly is  

m_f=0.55\ gr=0.00055\ kg

To have the same kinetic as the automobile:

\displaystyle \frac{m_fv_f^2}{2}=25,000

Solving for v_f

\displaystyle v_f=\sqrt{\frac{2(25,000))}{m_f}}

\displaystyle v_f=\sqrt{\frac{50,000}{0.00055}}

v_f=9,534.6\ m/s

The fly should need to move at 9,534.6 m/s to have the same kinetic energy as the automobile

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Answer:

a = 3.61[m/s^2]

Explanation:

To find this acceleration we must remember newton's second law which tells us that the total sum of forces is equal to the product of mass by acceleration.

In this case we have:

F = m*a\\\\m=mass = 3.6[kg]\\F = force = 13[N]\\13 = 3.6*a\\a = 3.61[m/s^2]

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What is sludge dumping? Sludge is the solid waste in raw sewage. Sludge dumping is discharging that waste into the ocean.

Explanation:

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Thiết bị trao đổi nhiệt ngược chiều, nhiệt độ chất lỏng nóng vào là 310°C, ra là 115°c. Nhiệt độ chất lỏng lạnh vào là 25°c và r
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A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7 1010 m (inside the orbit
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Answer:

58515.9 m/s

Explanation:

We are given that

d_1=4.7\times 10^{10} m

v_i=9.5\times 10^4 m/s

d_2=6\times 10^{12} m

We have to find the speed (vf).

Work done by surrounding particles=W=0 Therefore, initial energy is equal to final energy.

K_i+U_i=K_f+U_f

\frac{1}{2}mv^2_i-\frac{GmM}{d_1}=\frac{1}{2}mv^2_f-\frac{GmM}{d_2}

\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2}=\frac{1}{2}v^2_f

v^2_f=2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})

v_f=\sqrt{2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})}

Using the formula

v_f=\sqrt{v^2_i+2GM(\frac{1}{d_2}-\frac{1}{d_1})}

v_f=\sqrt{(9.5\times 10^4)^2+2\times 6.7\times 10^{-11}\times 1.98\times 10^{30}(\frac{1}{6\times 10^{12}}-\frac{1}{4.7\times 10^{10})}

Where mass of sun=M=1.98\times 10^{30} kg

G=6.7\times 10^{-11}

v_f=58515.9 m/s

4 0
3 years ago
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