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3 years ago

Which best describes accuracy?

Physics

2 answers:

zysi [14]3 years ago

4 0

Answer:

the agreement between a measured value and an accepted value

Explanation:

Vitek1552 [10]3 years ago

3 0

Answer: A.) the smallness of the graduations on a measuring tool

Explanation:

Accuracy is defined as the closeness of the measured value to the actual value. Therefore, out of the options, this is best described by A. the smallness of the graduations on a measuring tool. This is because smaller graduations mean that the value can be measured to a smaller level, making it more accurate. PLEASE GIVE ME BRAINIEST

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Using the picture above, which ball has the greatest potential energy?

weqwewe [10]

Ball 4 because the higher the elevation is the greater the potential energy it has

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2 years ago

The number of confirmed exoplanets is (a) less than 10; (b) roughly 50; (c) more than 500; (d) more than 5000.

Bad White [126]

Answer:

Explanation:

Until 2019, more than 3000 planetary systems have been discovered that contain more than 4000 exoplanets, since some of these systems contain multiple planets. Most known extrasolar planets are gas giants equal to or more massive than the planet Jupiter, with orbits very close to its star.

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3 years ago

A car is moving at a constant speed of 100 miles per hour. how long does it take for the car to travel 200 miles.

Pepsi [2]

Answer:

d. 2 hours

Explanation:

because if it travels 100 miles per hour in 1 hour it would travel 200 miles in 2 hours and so fourth.

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2 years ago

Manuel is holding a 5 kg box. How much force us the box exerting on him? in what direction

Free_Kalibri [48]

It will be 49 Newtons of force in the down direction. To find the force in newtons, you multiply the mass (5 kg) by the gravity (which if 9.8).

3 0

3 years ago

A solid conducting sphere of radius 2 cm has a charge of 8microCoulomb. A conducting spherical shell of inner radius 4 cm andout

nika2105 [10]

Answer:

C) 7.35*10⁶ N/C radially outward

Explanation:

If we apply the Gauss'law, to a spherical gaussian surface with radius r=7 cm, due to the symmetry, the electric field must be normal to the surface, and equal at all points along it.
So, we can write the following equation:

$E*A = \frac{Q_{enc} }{\epsilon_{0}} (1)$

As the electric field must be zero inside the conducting spherical shell, this means that the charge enclosed by a spherical gaussian surface of a radius between 4 and 5 cm, must be zero too.
So, the +8 μC charge of the solid conducting sphere of radius 2cm, must be compensated by an equal and opposite charge on the inner surface of the conducting shell of total charge -4 μC.
So, on the outer surface of the shell there must be a charge that be the difference between them:

$Q_{enc} = - 4e-6 C - (-8e-6 C) = + 4 e-6 C$

Replacing in (1) A = 4*π*ε₀, and Qenc = +4 μC, we can find the value of E, as follows:

$E = \frac{1}{4*\pi*\epsilon_{0} } *\frac{Q_{enc} }{r^{2} } = \frac{9e9 N*m2/C2*4e-6C}{(0.07m)^{2} } = 7.35e6 N/C$

As the charge that produces this electric field is positive, and the electric field has the same direction as the one taken by a positive test charge under the influence of this field, the direction of the field is radially outward, away from the positive charge.

6 0

3 years ago