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Marina86 [1]
2 years ago
15

1. Can someone help me with this? :) Which object is made of frozen gas, ice, and dust that orbits in the outermost reaches of t

he solar system?
1) planet
2) moon
3) Kuiper Belt object
4) meteor

2. Which explanation of the solar system best fits the observations of the planets and how they orbit the sun?
1) A comet hit the sun and sent off fragments that became the planets.
2) The gravity of a large, massive star passing the sun ripped off blobs of material from it that formed the planets.
3) The planets formed at the center of a collapsing spinning cloud of gas and dust.
4) The sun and planets formed from a collapsing spinning cloud of gas and dust.
Physics
1 answer:
Rus_ich [418]2 years ago
3 0
<span>1. Kuiper Belt object is made of frozen is made of frozen gas, ice, and dust that orbits in the outermost reaches of the solar system. Kuiper belt is a region which is filled with icy gaz bodies. Its structure is almost the same as the asteroid belt between Mars and Jupiter. Pluto, Makemake, Haumea are the officially recognized planets which are located in this region. 2. In my opinion, the most suitable option is: 3) The planets formed at the center of a collapsing spinning cloud of gas and dust. According to theory of solar system formation, the solar system appeared after a supernova (star explosion). A cloud of gas and dust was collapsed, and it caused a formation of a solar nebula.

</span>
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Find the magnitude of the sum of two vectors; A is 5 km , and B is 7 , when the angle btween them is 120
Dimas [21]

Answer: 6.24 km

Explanation:

Given

The magnitude of the first vector(say) \left |  a\right |=5\ km

the magnitude of the second vector(say) \left |  b\right |=7\ km

the angle between them is 120^{\circ}

The resultant vector magnitude is given by

\left |  \vec{R}\right |=\sqrt{a^2+b^2+2ab\cos \theta}

\left |  \vec{R}\right |=\sqrt{5^2+7^2+2\times 5\times 7\cdot \cos 120^{\circ}}\\\left |  \vec{R}\right |=\sqrt{74-35}=\sqrt{39}\\\left |  \vec{R}\right |=6.24\ km

4 0
2 years ago
Refraction occurs through a glass slab why​
masha68 [24]

Answer:

One when it enters the glass slab from air and second time when it enters the air through glass slab. When light rays travelling through air enters glass slab, they get refracted and bend towards the normal. Now the direction of refracted ray changes again when it comes out of the glass slab into air.

8 0
2 years ago
A race car accelerates from 0 m/s to 30.0 m/s with a displacement of
worty [1.4K]

Answer:

4. 10.0 m/s²

Explanation:

I) if initial velocity is 'v₀', the final velocity is 'v', the accelaration is 'a', the distance is 'L' and elapsed time if 't', then:

1. \ a=\frac{v-v_0}{t};

2. \ L=\frac{at^2}{2}.

II) using these two equations after substitution v₀=0; v=30 and L=45:

\left \{{{45 =\frac{at^2}{2}} \atop {a=\frac{30-0}{t} }} \right.

\left \{ {{at^2=90} \atop {at=30}} \right. \  \ \left \{ {{a=10} \atop {t=3}} \right. => \ a=10\frac{m}{s^2}

6 0
3 years ago
Which cycle causes earthquake and volcanic activity? carbon water tectonic phosphorus
erik [133]
The answer would be tectonic. hope this helps (:
6 0
3 years ago
Read 2 more answers
Unpolarized light with an average intensity of 845 W/m2 moves along the x-axis when it enters a Polarizer A with a vertical tran
horsena [70]

Answer:

θ = 36.2º

Explanation:

When light passes through a polarizer it becomes polarized and if it then passes through a second polarizer, it must comply with Malus's law

         I = I₀ cos² tea

The non-polarized light between the first polarized of this leaves half the intensity, with vertical polarization

          I₁ = I₀ / 2

          I₁ = 845/2

          I₁ = 422.5 W / m²

In this case, the incident light in the second polarizer has an intensity of I₁ = 422.5 W / m² and the light that passes through the polarizer has a value of

I = 275 W / m ²

      Cos² θ = I / I₁

      Cos θ = √ I / I₁

      Cos θ = √ (275 / 422.5)

     Cos θ = 0.80678

     θ = cos⁻¹ 0.80678

     θ = 36.2º

This is the angle between the two polarizers

8 0
3 years ago
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