4. A baseball is pitched with a speed of 35 m/s. If the baseball has a mass of 0.146 kg, what is its

A rectangular block floats in pure water with 0.400 in. above the surface and 1.60 in. below the surface. When placed in an aque

labwork [276]

Answer:

specific gravity = 0.8

specific gravity of solution = 2

Explanation:

given data

rectangular block above water = 0.400 in

rectangular block below water = 1.60 in

material floats below water = 0.800 in

solution

first we get here specific gravity of block that is

specific gravity = block vol below ÷ total block vol × specific gravity water ..............1

put here value we get

specific gravity = $\frac{1.60}{1.60+0.400}$ × 1

specific gravity = 0.8

and now we get here specific gravity of solution that is express as

specific gravity of solution = total block vol ÷ block vol below × specific gravity block ........................2

put here value we get

specific gravity of solution = $\frac{1.60+0.400}{0.800}$ × 0.8

specific gravity of solution = 2

6 0

2 years ago

A 0.25 kg ball is suspended from a light 0.65 m string as shown. The string makes an angle of 31° with the vertical. Let U = 0 w

steposvetlana [31]

Explanation:

a) The height of the ball h with respect to the reference line is

$h = L - L\cos{31°} = L(1 - \cos{31°})$

so its initial gravitational potential energy $U_0$ is

$U = mgh = mgL(1 - \cos{31°})$

$\:\:\:\:\:=(0.25\:\text{kg})(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31})$

$\:\:\:\:\:=0.23\:\text{J}$

b) To find the speed of the ball at the reference point, let's use the conservation law of energy:

$\Delta{K} + \Delta{U} = 0 \Rightarrow K_0 + U_0 = K + U$

We know that the initial kinetic energy $K_0,$ as well as its final gravitational potential energy $U$ are zero so we can write the conservation law as

$mgL(1 - \cos{31°}) = \frac{1}{2}mv^2$

Note that the mass gets cancelled out and then we solve for the velocity v as

$v = \sqrt{2gL(1 - \cos{31°})}$

$\:\:\:\:\:= \sqrt{2(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31°})}$

$\:\:\:\:\:= 1.3\:\text{m/s}$

5 0

2 years ago

Read 2 more answers

Please Help! (15 POINTS)

murzikaleks [220]

Answer:

160 Nm

Explanation:

5 0

2 years ago

In a physics lab, you measure the vibrational-rotational spectrum of hcl. the estimated separation between absorption peaks is:_

BlackZzzverrR [31]

The appropriate value in blank given is Δf = 5.5 x $10^{11}$ Hertz.

We have vibrational - rotational spectrum Hydrochloric Acid.

We have to investigate the estimated separation between absorption peaks and fill the blank.

<h3>What is vibrational - rotational spectrum ?</h3>

Rotational–vibrational spectroscopy is a branch of molecular spectroscopy. It deals with the infrared and Raman spectra of molecules in the gaseous phase.

According to the question -

The estimated separation between absorption peaks in the vibrational-rotational spectrum of HCl is denoted by Δf and is equal to -

Δf = 5.5 x $10^{11}$ Hertz

Hence, the appropriate value in blank given is Δf = 5.5 x $10^{11}$ Hertz.

To learn more about vibrational-rotational spectrum, visit the link below-

brainly.com/question/18403840

#SPJ4

8 0

1 year ago

A projectile is fired vertically from Earth's surface with

scoray [572]

Answer: