Question

A gas that exerts a pressure of 15.6 psi in a container with the volume of ______ L will exert a pressure of 24.43 psi when transferred to a container with a volume of 1.895 L.

Answer 1

Boyle's Law states: pV = constant.

24.43 x 1.895 = 46.29485

therefore, 15.6 x _____ = 46.29485

unknown = 2.968L

Answer 2

Answer:

The initial volume of the container = 2.97 L

Explanation:

Given:

Initial pressure of gas, P1 = 15.6 psi

Final pressure of gas, P2 = 24.43 psi

Final volume, V2 = 1.895 L

To determine:

The initial volume V1 occupied by the gas

Explanation:

Based on the ideal gas equation

$PV = nRT$

where P = pressure, V = volume ; n = moles of gas

R = gas constant, T = temperature

At constant n and T, the above equation becomes:

PV = constant

This is the Boyle's law

Therefore:

$P1V1 = P2V2\\\\V1 = \frac{P2V2}{P1} = \frac{24.43 \ psi*1.895\ L}{15.6\ psi} =2.97\ L$