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zalisa [80]
3 years ago
7

Two source charges are placed close together. The electric field vectors close to the charges all point toward the charge on the

right and away from the charge on the left. A positive test charge is released in the middle. Which way will the test charge move?
A.
to the right
B.
to the left
C.
up
D.
down
Physics
1 answer:
Leto [7]3 years ago
5 0
B is the correct answer i believe
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Which one of the following temperatures is equal to 5°C?
natali 33 [55]

Answer : The correct option is, (D) 278 K

Explanation :

We are given temperature 5^oC.

Now the conversion factor used for the temperature is,

K=^oC+273

where, K is kelvin and ^oC is Celsius.

Now put the value of temperature, we get

K=5^oC+273=278K

Therefore, the temperature 278 K is equal to the 5^oC


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Young _____ stars would most likely be found in a giant molecular cloud.
marysya [2.9K]
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how do organisms interact with the living and the non-living environment to obtain matter and energy?​
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3 years ago
Consult Multiple-Concept Example 9 to explore a model for solving this problem. A person pushes on a 63-kg refrigerator with a h
miskamm [114]

Answer:

 a ) 270 N

b )413.65 N

Explanation:

weight of the refrigerator = reaction force ( R )

= mg

= 63 x 9.8

R = 617.4 N

Maximum friction possible

= coefficient of friction x R

= .67 X 617.4

= 413.65 N

When force 270 N is applied , due to friction,  the body does not move .

The friction force adjusts itself to the external applied force to prevent the body to budge.

Hence the friction force acting in this situation = 270 N

b ) The maximum friction possible is 413.65 . If we apply a force equal to or exceeding 413.65 N , body will move. Hence 413.65 N is the answer.

4 0
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pashok25 [27]

Answer:

Explanation:

Given that the angular velocity is constant.

The actual weight is W = 549N

The ride apparent weight is

W' = 1.5N

Apparent weight at the top of the ride?

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ar is the radial acceleration

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N = mg —m•ar

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The apparent weight is equal to the normal

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W'(top) = m(g—ar)

W'(top) = mg —m•ar

We know that the actual weight is

W=mg

Also, the apparent weight is

W' = m•ar

Then

W'(top) = Actual weight - apparent

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W'(top) = 547.5 N

8 0
4 years ago
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