Question

To determine the specific heat of an object, a student heats it to 100 degrees C in boiling water. She then places the 110 g object in a 172 g aluminum calorimeter containing 148 g of water. The aluminum and water are initially at a temperature of 19.6 degrees, and are thermally insulated from their surroundings.
If the final temperature is 23.8 degrees, what is the specific heat of the object?

Answer 1

Answer:

Cs=912.6J/kg/K

Explanation:

Sum of Heat gained=sum heat lośs

Definition of terms

Ms=mass of substance 0.11kg

Cs=specific heat capacity of the substance?

Ts= temperature of the substance

Tm= temperature of mixture 28.8°C

Tal= temperature of aluminium19.6°C

Tw=temperature of water 19.6°C

Mal=mass of aluminium 0.172kg

Mw=mass of water 0.148kg

Cw= specific heat capa of water 4200j/kgk

Cal=specific heat capacity of aluminium 903j/kgk

Having gotten all the parameters needed

Ms*Cs*(Ts-Tm)=Mw*Cw*(Tm-Tw) +Mal*Cal*(Tm-Tal)

0.11*Cs*(100-28.8)=0.148*4200*(28.8-19.6) +0.172*903*(28.8-19.6)

cs==((4467267)/(4895))

Cs=912.61Jkg–1K–1