Given the final velocity (Vf) and the acceleration (a), the distance that should be traveled by the plane is calculated through the equation,
d = (Vf² - Vi²) / 2a
V1 should be zero because the light plane started the motion from rest. Substituting the given values,
d = ((33 m/s)² - 0)) / 2(3 m/s²)
The distance is therefore equal to 181.5 meters.
Answer:
impulse acting on it
Explanation:
The impulse is defined as the product between the force applied to an object (F) and the time interval during which the force is applied (
):

We can prove that this is equal to the change in momentum of the object. In fact, change in momentum is given by:

where m is the mass and
is the change in velocity. Multiplying and dividing by
, we get

and since
is equal to the acceleration, a, we have

And since the product (ma) is equal to the force, we have

which corresponds to the impulse.
It is B since they are traveling at the same speed one is positive so the other had to be negative hope this helps;)))))