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4 years ago

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A tetrahedron has an equilateral triangle base with 20-cm-long edges and three equilateral triangle sides. The base is parallel

to the ground, and a vertical uniform electric field of strength 200 N/C passes upward through the tetrahedron.
What is the electric flux through the base?

1 answer:

SVETLANKA909090 [29]4 years ago

6 0

Answer:

electric flux through the base is 3.45 m²/C

Explanation:

given data

base length = 20 cm

uniform electric field of strength = 200 N/C

solution

as base is perpendicular to filed flux through the base

Ф = - $\frac{\sqrt{3} }{4}$ × E × a² .......................1

here E is strength of electric field and a is side

so put here value in equation 1 we get

Ф = - $\frac{\sqrt{3} }{4}$ × 200 × 0.20²

Ф = 3.45 m²/C

so electric flux through the base is 3.45 m²/C

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Answer:

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Explanation:

Let L represent Moe's height during the leap.

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We need to integrate equation 1 with respect to t

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L = ut - 0.5gt^2 + L₀

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Answer:

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Answer: 271.4 s

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Where:

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Finding this time:

$\Delta t=\frac{V_{f}-V_{o}}{a_{ave}}$ (2)

$\Delta t=\frac{90.74 m/s - 0 m/s}{0.89 m/s^{2}}$ (3)

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Now we have to find the distance $d$ the car traveled at this maximum speed with the following equation:

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Isolating $d$ :

$d=\frac{V_{f}^{2}}{2a_{ave}}$ (6)

$d=\frac{(90.74 m/s)^{2}}{2(0.89 m/s^{2})}$ (7)

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On the other hand, we know the total distance $D$ traveled by the car is:

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$t_{2}=\frac{15362.35 m}{90.74 m/s}$ (13)

$t_{2}=169.45 s$ (14)

With this time $t_{2}$ and the value of $t_{1}$ calculated in (4) we can finally calculate the total time $t_{TOTAL}$ :

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pishuonlain [190]

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4 years ago

Read 2 more answers