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Iteru [2.4K]
4 years ago
15

A tetrahedron has an equilateral triangle base with 20-cm-long edges and three equilateral triangle sides. The base is parallel

to the ground, and a vertical uniform electric field of strength 200 N/C passes upward through the tetrahedron.
What is the electric flux through the base?
Physics
1 answer:
SVETLANKA909090 [29]4 years ago
6 0

Answer:

electric flux through the base is 3.45 m²/C

Explanation:

given data

base length = 20 cm

uniform electric field of strength = 200 N/C

solution

as base is perpendicular to filed flux through the base

Ф = - \frac{\sqrt{3} }{4} × E × a² .......................1

here E is strength of electric field and a is side

so put here value in equation 1 we get

Ф = - \frac{\sqrt{3} }{4} × 200 × 0.20²

Ф =  3.45 m²/C

so electric flux through the base is 3.45 m²/C

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While visiting the planet Mars, Moe leaps straight up off the surface of the Martian ground with an initial velocity of 105 m/s
yawa3891 [41]

Answer:

L = 0 m

Therefore, the cricket was 0m off the ground when it became Moe’s lunch.

Explanation:

Let L represent Moe's height during the leap.

Moe's velocity v at any point in time during the leap is;

v = dL/dt = u - gt .......1

Where;

u = it's initial speed

g = acceleration due to gravity on Mars

t = time

The determine how far the cricket was off the ground when it became Moe’s lunch.

We need to integrate equation 1 with respect to t

L = ∫dL/dt = ∫( u - gt)

L = ut - 0.5gt^2 + L₀

Where;

L₀ = Moe's initial height = 0

u = 105m/s

t = 56 s

g = 3.75 m/s^2

Substituting the values, we have;

L = (105×56) -(0.5×3.75×56^2) + 0

L = 0 m

Therefore, the cricket was 0m off the ground when it became Moe’s lunch.

5 0
3 years ago
A loaded 500 kg sled is traveling on smooth horizontal snow at 5 m/s when it suddenly comes to a rough region. The region is 10
sergejj [24]

Answer:

400 N

Explanation:

Change of Kinetic Energy to Friction Wok

∆KE = W

½ x m x (v(5)² - v(3)²) = f x d

½ x 500 x (5² - 3²) = f x 10

250 x (25 - 9) = f x 10

25 x 16 = f

f = 400 N

6 0
3 years ago
The fastest time ever run at Pikes Peak is 7:57. That’s way too long. If we removed all the curves, making a straight line from
anygoal [31]

Answer: 271.4 s

Explanation:

We are told the top speed (maximum speed) V_{max} the car has is:

V_{max}=203 mph=90.74 m/s taking into account 1 mile=1609.34 m

And the car's average acceleration a_{ave} is:

a_{ave}=0.091 g=2.93 ft/s^{2}=0.89 m/s^{2}

Since:

a_{ave}=\frac{V_{f}-V_{o}}{\Delta t} (1)

Where:

V_{f}=V_{max}=90.74 m/s is the car's final speed (top speed)

V_{o}=0 m/s because it starts from rest

\Delta t is the time it takes to reach the top speed

Finding this time:

\Delta t=\frac{V_{f}-V_{o}}{a_{ave}} (2)

\Delta t=\frac{90.74 m/s - 0 m/s}{0.89 m/s^{2}} (3)

\Delta t=t_{1}=101.95 s (4)

Now we have to find the distance d the car traveled at this maximum speed with the following equation:

V_{f}^{2}=V_{o}^{2} + 2a_{ave} d (5)

Isolating d:

d=\frac{V_{f}^{2}}{2a_{ave}} (6)

d=\frac{(90.74 m/s)^{2}}{2(0.89 m/s^{2})} (7)

d=4625.70 m (8)

On the other hand, we know the total distance D traveled by the car is:

D=12.42 miles = 19988.052 m

Hence the remaining distance is:

d_{remain}=D-d=19988.052 m - 4625.70 m (9)

d_{remain}=15362.35 m (10)

So, we can calculate the time t_{2} it took to this car to travel this remaining distance d_{remain} at its top speed V_{max}, with the following equation:

V_{max}=\frac{d_{remain}}{t_{2}} (11)

Isolating t_{2}:

t_{2}=\frac{d_{remain}}{V_{max}} (12)

t_{2}=\frac{15362.35 m}{90.74 m/s} (13)

t_{2}=169.45 s (14)

With this time t_{2} and the value of t_{1} calculated in (4) we can finally calculate the total time t_{TOTAL}:

t_{TOTAL}=t_{1}+ t_{2} (15)

t_{TOTAL}=101.95 s + 169.45 s (16)

t_{TOTAL}=271.4 s s

5 0
4 years ago
A light bulb has a power rating of 60 W. What is the current running into it if it is plugged into a 120 V outlet?
kifflom [539]

Answer:

0.5 Amperes

Explanation:

Information that we have:

Power: P=60W

Voltage: V=120V

and we use the equation that relates this two quantities to the Current (I):

I=\frac{P}{V}

where I is the curent, P is the Power and V is the Voltage.

we substitute the values given for the Power and the Voltage to find the current:

I=\frac{60W}{120V}\\ I=0.5A

the Current running into the bulb is 0.5 Amperes

3 0
3 years ago
What is the average speed of a cheetah that runs 88m in 5 seconds?
pishuonlain [190]

17.6 m/s


is the answer



v=displacent/time



Hope i helped <333



5 0
4 years ago
Read 2 more answers
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