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kap26 [50]
3 years ago
13

A loaded 500 kg sled is traveling on smooth horizontal snow at 5 m/s when it suddenly comes to a rough region. The region is 10

m long and reduces the sled's speed to 3 m/s what average friction force did the rough region exert on the sled?
Physics
1 answer:
sergejj [24]3 years ago
6 0

Answer:

400 N

Explanation:

Change of Kinetic Energy to Friction Wok

∆KE = W

½ x m x (v(5)² - v(3)²) = f x d

½ x 500 x (5² - 3²) = f x 10

250 x (25 - 9) = f x 10

25 x 16 = f

f = 400 N

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A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A
Flura [38]

Answer:

The mass of the wheel is 2159.045 kg

Explanation:

Given:

Radius r = 0.330

m

Force F = 290 N

Angular acceleration \alpha  = 0.814 \frac{rad}{s^{2} }

From the formula of torque,

 Γ = I\alpha                                        (1)

 Γ = rF                                       (2)

rF = I \alpha

Find momentum of inertia I from above equation,

I = \frac{rF}{\alpha }

I = \frac{0.330 \times 290}{0.814}

I = 117.56 Kg. m^{2}

Find the momentum inertia of disk,

 I = \frac{1}{2}  Mr^{2}

M = \frac{2I}{r^{2} }

M = \frac{2 \times 117.56}{(0.330)^{2} }

M = 2159.045 Kg

Therefore, the mass of the wheel is 2159.045 kg

8 0
3 years ago
Hans Full is pulling on a rope to drag his backpack to school across the ice. He pulls upwards and rightwards with a force of 22
natka813 [3]

Answer:

2420 J

Explanation:

From the question given above, the following data were obtained:

Force (F) = 22.9 N

Angle (θ) = 35°

Distance (d) = 129 m

Workdone (Wd) =?

The work done can be obtained by using the following formula:

Wd = Fd × Cos θ

Wd = 22.9 × 129 × Cos 35

Wd = 22.9 × 129 × 0.8192

Wd ≈ 2420 J

Thus, the workdone is 2420 J.

3 0
3 years ago
Why are latitude and longitude included on maps
Veseljchak [2.6K]

Answer:

to locate places on earth

3 0
2 years ago
What is the final velocity of a car that starts at 22 m/s and accelerates at 3.78 m/s for distance of 45 m
Pepsi [2]

v^2 = v0^2 +2ad v^2 = 22^2 + 2*3.78*45 = 824.2 v= √824.2 = 28.7 m/s

5 0
3 years ago
Finding the spring constant as shown, spring 3, which has an unknown spring constant k3, replaces spring 2. the mass of the weig
nevsk [136]
Replaces spring 2. the mass of the weight and pulley are unchanged: m=5.8 kg and mp=1.7 kg
6 0
3 years ago
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