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LekaFEV [45]
3 years ago
11

As the video states, a person weighs less on the moon than on

Physics
1 answer:
sveticcg [70]3 years ago
8 0

Answer:

then if there was no gravity, everyone would be lighter and floating but if there was a lot of gravity everyone would be pulled towards the ground very heavily and make us heavier

Explanation:

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You drop a steel ball bearing, with a radius of 2.40 mm, into a beaker of honey. Note that honey has a viscosity of 6.00 Pa/s an
Stells [14]

Answer:

The “terminal speed” of the ball bearing is 5.609 m/s

Explanation:

Radius of the steel ball R = 2.40 mm

Viscosity of honey η = 6.0 Pa/s

\text { Viscosity has Density } \sigma=1360 \mathrm{kg} / \mathrm{m}^{3}

\text { Steel has a density } \rho=7800 \mathrm{kg} / \mathrm{m}^{3}

\left.\mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^{2} \text { (g is referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^{2} \text { on Earth }\right)

While calculating the terminal speed in liquids where density is high the stokes law is used for viscous force and buoyant force is taken into consideration for effective weight of the object. So the expression for terminal speed (Vt)

V_{t}=\frac{2 \mathrm{R}^{2}(\rho-\sigma) \mathrm{g}}{9 \eta}

Substitute the given values to find "terminal speed"

\mathrm{V}_{\mathrm{t}}=\frac{2 \times 0.0024^{2}(7800-1360) 9.8}{9 \times 6}

\mathrm{V}_{\mathrm{t}}=\frac{0.0048 \times 6440 \times 9.8}{54}

\mathrm{V}_{\mathrm{t}}=\frac{302.9376}{54}

\mathrm{V}_{\mathrm{t}}=5.609 \mathrm{m} / \mathrm{s}

The “terminal speed” of the ball bearing is 5.609 m/s

7 0
3 years ago
What do refrigerators and air conditioners use to move heat?
Aleksandr [31]
your answer is Freon
3 0
3 years ago
Read 2 more answers
What are 3 subatomic particles of an atom?
Vesnalui [34]
Protons, neutrons, and electrons<span> are the three main subatomic particles found in an atom.</span>
7 0
3 years ago
Read 2 more answers
Which statement best describes a primary source?
Fantom [35]

Answer:

I go with D but what you can do is u can read each and choose the one that sounds right Hope this helps

3 0
3 years ago
A block of aluminium of density 7900 kg/m3 has a volume of 250 cm. Find the<br>mass of the block.​
pashok25 [27]

Answer:

mass of block=2.7 gm

Explanation:

concept: Density=mass/volume

given:ρ=2700 kg/m^3 and v=250 cm^3 (in cm^3 not in m^3)

=> v= convert cm^3 to m^3

there fore= 1 cm^3=1 cm*1 cm*1 cm

i.e 1 cm^3=1/100*1/00*1/100 m^3 => 1 cm^3=1/1000000 m^3

ρ=m/v

=>mass=ρ*volume

=>mass=2700*1/10^-6

=>mass=2.7*10^-3 kg =>2.7 gm

8 0
2 years ago
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