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ryzh [129]
3 years ago
6

The atomic mass of an element is equal to the number of:

Chemistry
2 answers:
Xelga [282]3 years ago
5 0
Protons plus neutrons
Yuliya22 [10]3 years ago
4 0

Answer:

the answer is B

Explanation:

ik this bc i had it on a test that was the correct answer.

WORK

I LOVE HAMEILTON

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The carbon-magnesium bond in a Grignard reagent is covalent and highly-polarized such that the carbon is negatively charged. Whi
goldenfox [79]

Answer:

Option 3 - Grignard reagents are strong bases and option 4 - Grignard reagents are strong nucleophiles

Explanation:

The carbon in grignard reagent has a very strong carbanionic character which gives grignard reaction it's unique characteristic of a strong base and strong nucleophile.

RCH_{2} - x + M_{g}  ⇒   RCH_{2}^{o- o+} Mgx

8 0
4 years ago
what is a measure of the amount of matter in an object while what is a measure of the force of gravity acting on an object
masha68 [24]
A measure for the amount of matter in an object would be grams or kilograms.
the measure of the force of gravity acting on an object would be newtons.

the amount of matter in an object is called mass.
the force of gravity acting upon an object would be called weight.
7 0
3 years ago
5 What is the concentration of a 25.0 mL HCl solution containing a phenolphthalein indicator that is titrated with 0.1 M NaOH if
Neporo4naja [7]
The correct answer is 0.137 M.

4 0
3 years ago
Read 2 more answers
Choose the products that complete the reaction. The chemical equation may not be balanced.
Alina [70]

Al2(SO4)3 + H2

Explanation:

8 0
4 years ago
Read 2 more answers
What mass of carbon dioxide is formed when 1.75 mol of ethane burns completely in oxygen?
dybincka [34]

Answer:

There is a mass of 154 Grams of Carbon Dioxide.

Explanation:

One mole is equal to 6.02 × 10^23 particles.

This means we have 1.05 X 10^24 total particles of Ethane.

Each ethane particle contains 2 carbon atoms.

If every particle of ethane is burned, we will end up with 2.10 x 10^24 molecules of Carbon Dioxide (Particles of Methane x 2, since each Methane particle contains 2 carbon atoms)

Carbon Dioxide has a molar mass of 44.01 g/mol

So if we take our amount of Carbon Dioxide molecules and divide it by 1 mole, ((2.10 x 10^24)/(6.02 x 10^23) = 3.49) we find that we have 3.49 moles of Carbon Dioxide.

Now all we need to do is multiply our moles of carbon dioxide(3.49) by it's molar mass(44.01) while accounting for significant digits.

What you should end up with is 154 Grams of Carbon Dioxide.

Hope this helps (And more importantly I hope I didn't make any errors in my math lol)

As a side note this is all assuming that this takes place at STP conditions.

3 0
3 years ago
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