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3 years ago

What is the reaction used to join the fatty acid to the glycerol molecule?

Chemistry

1 answer:

m_a_m_a [10]3 years ago

3 0

Answer:

The reaction that is used to join fatty acid and glycerol is known as Lipogenesis.

Explanation:

Lipogenesis is an important anabolic pathway that helps in the biosynthesis of triacylglycerol by joining glycerol with fatty acid by ester linkage.Lipogenesis occur in liver and adipose tissue .

Lipogenesis takes place in our body to store excess fatty acid in form of triacylglycerol which is a complex lipid molecule.

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3. Which muscle tissue lacks striations?

Diano4ka-milaya [45]

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your answer is b and hope ur help and mark me brainlist

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2 years ago

Mn2+(aq) + nabio3(s) → bi3+(aq) + mno4−(aq) + na+(aq) how many water molecules are there in the balanced equation (for the react

stiks02 [169]

Mn²⁺ + 4H2O -----> MnO4⁻ + 8H⁺ +5e⁻ /*2
NaBiO3 +6H⁺ +2e⁻ -----> Bi³⁺ + Na⁺ + 3H2O /*5
2Mn²⁺ + 5 NaBiO3+8H2O+30H⁺ ---> 2MnO4⁻ +5Bi³⁺ + 5Na⁺ +16H⁺ +15H2O

2Mn²⁺ + 5 NaBiO3+14H⁺ ---> 2MnO4⁻ +5Bi³⁺ + 5Na⁺ +7H2O

There are 7 water molecules in this reaction.

4 0

2 years ago

Read 2 more answers

An internal combustion engine relies primarily on the efficient production of energy by the combination of oxygen (02) and gasol

jeka57 [31]

Answer is: the exact ratio of oxygen to octane for is 12.5 : 1.
Balanced chemical reaction: C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O or multiply by 2:
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O.
There same number of atoms on both side of balanced chemical reaction: eight carbon atoms, eighteen hydrogen atoms and twenty five oxygen atoms.

7 0

2 years ago

Consider the addition of HBr to 2-pentene. Indicate the re

lana [24]

Answer:

This addition reaction yields 3-BromoPentane and 2-BromoPentane.

Explanation: The reaction is an addition reaction that follows the Markonikoff's principle engaging the electrophillic addition mechnism with electrophile having no lone pair so rearrangement of carbonation is possible. It yields two possible products.

5 0

3 years ago

Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4

inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

$M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol$

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

$M=\frac{n_{solute}}{V_{solution}}$

So you can solve for the moles of the solute:

$n_{solute}=M*V_{solution}$

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

$n_{solute}=1mol/L*1.5L=1.5mol$

But this is just a supposition.

Regards.

4 0

2 years ago