Question

(2x^3-4x^2-3x-9) by x-3

Answer 1

Answer:

2x² + 2x + 3

Step-by-step explanation:

x = 3 is a zero of both the numerator and the denominator, so the denominator will factor completely into the numerator with no remainder.  Using grouping to factor:

(2x³ − 4x² − 3x − 9) / (x − 3)

(2x³ − 4x² − 6x + 3x − 9) / (x − 3)

(2x (x² − 2x − 3) + 3x − 9) / (x − 3)

(2x (x − 3) (x + 1) + 3 (x − 3)) / (x − 3)

2x (x + 1) + 3

2x² + 2x + 3

To use long division instead, see image.