(2x^3-4x^2-3x-9) by x-3
1 answer:
Answer:
2x² + 2x + 3
Step-by-step explanation:
x = 3 is a zero of both the numerator and the denominator, so the denominator will factor completely into the numerator with no remainder. Using grouping to factor:
(2x³ − 4x² − 3x − 9) / (x − 3)
(2x³ − 4x² − 6x + 3x − 9) / (x − 3)
(2x (x² − 2x − 3) + 3x − 9) / (x − 3)
(2x (x − 3) (x + 1) + 3 (x − 3)) / (x − 3)
2x (x + 1) + 3
2x² + 2x + 3
To use long division instead, see image.
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