The pH at the equivalence point always not equal to 7 in a neutralization titration when titration occur between weak acid and weak base , strong acid and weak base or strong base weak acid. The reason behind it is given as,
- At equivalence point the product is present by reacting from acid and base.
- So, when weak acid titrate with strong base then the solution will be weak base at equivalence point.
When strong acid is neutralize with strong base then it form neutral product at the equivalence point. Hence the final conclusion is that the pH of the solution in which titration is takes place between strong acid and strong base is 7 that is neutral left titration between all type of acids and bases ha pH not equal to 7 .
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Answer:
Explanation:
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According to the reaction equation:
and by using ICE table:
CN- + H2O ↔ HCN + OH-
initial 0.08 0 0
change -X +X +X
Equ (0.08-X) X X
so from the equilibrium equation, we can get Ka expression
when Ka = [HCN] [OH-]/[CN-]
when Ka = Kw/Kb
= (1 x 10^-14) / (4.9 x 10^-10)
= 2 x 10^-5
So, by substitution:
2 x 10^-5 = X^2 / (0.08 - X)
X= 0.0013
∴ [OH] = X = 0.0013
∴ POH = -㏒[OH]
= -㏒0.0013
= 2.886
∴ PH = 14 - POH
= 14 - 2.886 = 11.11
Answer:
Below!
Explanation:
Isotopes are elements with a similar chemical makeup and the same atomic number, but a different atomic mass and number of neutrons . An example of this would be carbon-12, carbon-13, and carbon-14. Three isotopes of the element carbon that have the same 6 protons but have a different neutron count. A simple way to explain isotopes would be to say that they are just different "versions" of an element.
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Answer:
(A) 0.4M NaOH
Explanation:
The 20M NaOH caustic soda is diluted from 10mL to 500mL, that is:
500mL / 10mL = Is diluted 50 times.
That means we can solve the new concentration of the diluted solution dividing the stock concentration (20M) 50 times:
20M / 50 = 0.4M NaOH is the concentration of the diluted NaOH solution.
Right answer is:
<h3>(A) 0.4M NaOH</h3>
