Complete question is;
Lamar writes several equations trying to better understand potential energy. What conclusion is best supported by Lamar’s work?
A) The elastic potential energy is the same for any distance from a reference point.
B) The gravitational potential energy equals the work needed to lift the object.
C) The gravitational potential energy is the same for any distance from a reference point.
D) The elastic potential energy equals the work needed to stretch the object
Answer:
B) The gravitational potential energy equals the work needed to lift the object.
Explanation:
In physics, we know that potential energy is the energy of a body at rest while the energy of a body in motion is known as kinetic energy.
However,the work required to lift a body from it's position of rest is equal to the Gravitational potential energy of that body.
Elastic potential energy is the one that is stored as a result of force applied to deform an elastic object. Thus, it is not equal to the work needed to stretch the object and it is also not the same for any distance from reference point.
Thus, looking at the options, Option B is correct
Its not really definable. Say, you can have a full moon on the last day of November, and have the waning phases throughout the first half. Or you can have a new moon on the last day of December, and have the waxing phases during the first half of the month.
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Answer:
B
The plastic ball require lesser force than the iron ball
Answer:
7.68m/s
Explanation:
At point A, height h= 0m where v=?
At point B, height of h = 3.01 m above the top of the ramp v= 0 m/s
The conservation of energy here will be energy at Point A equals energy at point B
g= acceleration due to gravity= 9.81m/s^2
(mgh + 1/2 mv^2)A = (mgh + 1/2 mv^2)B
✓But height h at point A= 0 m then energy at point A= 1/2 mv^2
✓At point B , the velocity v= 0 m/s, then Energy at point B= mgh
✓ if we equate both energy at point A and B we have
mgh=1/2 mv^2
Let us make v the subject of formula, and cancel out the "m"
v=√2gh
Then substitute the values
V= √2×9.81×3.01
V=7.68m/s
Hence, his initial speed (in m/s) at point A is 7.68m/s
All bases have a pH above 7, so the solution that turned green (the soapy water) is basic.
