Let <em>a</em> denote the airplane's velocity in the air, <em>g</em> its velocity on the ground, and <em>w</em> the velocity of the wind. (Note that these are vectors.) Then
<em>a</em> = <em>g</em> + <em>w</em>
and we're given
<em>a</em> = (325 m/s) <em>j</em>
<em>w</em> = (55.0 m/s) <em>i</em>
Then
<em>g</em> = - (55.0 m/s) <em>i</em> + (325 m/s) <em>j</em>
The ground speed is the magnitude of this vector:
||<em>g</em>|| = √[ (-55.0 m/s)² + (325 m/s)² ] ≈ 330. m/s
which is faster than the air speed, which is ||<em>a</em>|| = 325 m/s.
Answer:
400 Newtons to the right.
Explanation:
You have 300 Newtons that are being applied to the right and you also 100 Newtons to the right. When calculating net force with the forces that go the same direction, you add them. 300 plus 100 is 400. Therefore, it is 400 Newtons or N to the right. Hope this helps!
Answer:
B
Explanation:
Simply take all forces pointing to the right of the box as positive and all of the forces pointing to the left of the box as negative and add all values.
ΣF = 7 + 18 + (-20) = 5N to the right
