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MrMuchimi
3 years ago
11

Put the following items in order of the scientific method:Draw conclusions. Ask a question. Develop a theory. Analyze data. Make

an observation. Experiment or test idea. Develop a hypothesis.
Physics
1 answer:
muminat3 years ago
6 0
Ask a question
Make an observation
Develop a hypothesis
Experiment
Analyse data 
Develop a theory
Hope this helped. :)
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3) Ęplain why muddy water is<br> Heterogeneous<br> mixture
nataly862011 [7]

Answer:

muddy water is a heterogeneous mixture, which is Suspension.

7 0
3 years ago
If the faster stone takes 12.0 s to return to the ground, how long will it take the slower stone to return?
iren [92.7K]
Same speed, because mass is neglected. The things that affect the speed are the distance and speed of the rock.
5 0
3 years ago
How much energy is needed to melt 5 g of ice? The specific latent heat of melting for water is 334000 J/kg.
Katen [24]

Answer:

The needed energy to melt of ice is 1670 J.

Explanation:

Given that,

Mass of ice = 5 g

Specific latent heat = 334000 J/kg

We need to calculate the energy

Using formula of energy

Q=mL

Where, m = mass

L = latent heat

Put the value into the formula

Q=5\times10^{-3}\times334000

Q=1670\ J

Hence, The needed energy to melt of ice is 1670 J.

5 0
3 years ago
An airplane propeller is 2.68 m in length (from tip to tip) and has a mass of 107 kg. When the airplane's engine is first starte
telo118 [61]

Answer:

a)30.14 rad/s2

b)43.5 rad/s

c)60633 J

d)42 kW

e)84 kW

Explanation:

If we treat the propeller is a slender rod, then its moments of inertia is

I =\frac{mL^2}{12} = \frac{107*2.68^2}{12} = 64.04 kgm^2

a. The angular acceleration is Torque divided by moments of inertia:

\alpha = \frac{T}{I} = \frac{1930}{64.04} = 30.14 rad/s^2

b. 5 revolution would be equals to 10\pi rad, or 31.4 rad. Since the engine just got started

\omega^2 = 2\alpha\theta = 2*30.14*31.4 = 1893.5

\omega = \sqrt{1893.5} = 43.5 rad/s

c. Work done during the first 5 revolution would be torque times angular displacement:

W = T*\theta = 1930 * 31.4 = 60633 J

d. The time it takes to spin the first 5 revolutions is

t = \frac{\omega}{\alpha} = \frac{43.5}{30.14} = 1.44 s

The average power output is work per unit time

P = \frac{W}{t} = \frac{60633}{1.44} = 41991 W or 42 kW

e.The instantaneous power at the instant of 5 rev would be Torque times angular speed at that time:

P_i = T*\omega = 1930*43.5=83983 W or 84 kW

7 0
3 years ago
A turtle ambles leisurely, as turtles tend to do, when it moves from a location with position vector 1,=1.91 m and 1,=−2.73 m in
Elena-2011 [213]

Answer:

Components: 0.0057, -0.0068. Magnitude: 0.0089 m/s

Explanation:

The displacement in the x-direction is:

d_x = 3.65-1.91=1.74 m

While the displacement in the y-direction is:

d_y = -4.79 -(-2.73)=-2.06 m

The time taken is t = 304 s.

So the components of the average velocity are:

v_x = \frac{d_x}{t}=\frac{1.74}{304}=0.0057 m/s

v_y = \frac{d_y}{t}=\frac{-2.06}{304}=-0.0068 m/s

And the magnitude of the average velocity is

v=\sqrt{v_x^2+v_y^2}=\sqrt{(0.0057)^2+(-0.0068)^2}=0.0089 m/s

8 0
3 years ago
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