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Hoochie [10]
3 years ago
6

Describe the three times acceleration can happen

Physics
2 answers:
Elden [556K]3 years ago
7 0

Answer:

There are three ways an object can accelerate: a change in velocity, a change in direction, or a change in both velocity and direction.

Explanation:

tigry1 [53]3 years ago
7 0

Answer:

A change in velocity, a change in direction, and a change in velocity and direction.

Explanation:

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f biofuel production and use reduces our consumption of imported fossil fuels, we may become less vulnerable to the adverse impacts of supply

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What two systems work with the digestive system to control digestion speed? a. Endocrine and Excretory c. Circulatory and Nervou
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A soccer player applies a force of 48.4 N to a soccer ball while kicking it. If the ball has
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C. 110 m/s2

Explanation:

Force = Mass x Acceleration

Since we have the force and the mass, we can rearrange this equation to solve for acceleration by dividing both sides by mass:

Force/Mass = (Mass x Acceleration)/Mass

Acceleration = Force/Mass

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Stairway must have uniform riser height and tread depth; variations in riser height or tread depth shall not be over _______ inc
alexandr1967 [171]

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\frac{3}{8} inches

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5 0
4 years ago
Two people stand facing each other at roller skating rink then push off each other
9966 [12]

a) 0 kg m/s

b) 0 kg m/s

c) +3 m/s

d) 60 N

Explanation:

a)

The momentum of an object is a vector quantity given by:

p=mv

where

m is the mass of the object

v is the velocity of the object

In this problem, we have a system of two people, so the total momentum will be the sum of the individual momenta of the two people:

p=p_1 + p_2

Which can be rewritten as

p=m_1 u_1 + m_2 u_2

where m_1,m_2 are the masses of the two people and u_1,u_2 their initial velocities.

However, the two people are initially at rest, so

u_1 = 0\\u_2 = 0

Therefore the total momentum is

p=0+0=0

b)

The principle of conservation of momentum states that when there are no external forces acting on a system, the total momentum of the system is conserved, so we can write:

p_i = p_f

where

p_i is the total momentum of the system before

p_f is the total momentum of the system after

In this problem,

p_i = 0

As we calculated in part a: this is because the total momentum of the two people before they push off each other is zero.

Therefore, according to the law of conservation of momentum,

p_f = p_i = 0

So the total momentum is zero also after they push off each other.

c)

The total momentum of the girl and the boy after they push off each other can be written as:

p_f = m_1 v_1 + m_2 v_2 (1)

where:

m_1 = 30 kg is the mass of the girl

v_1 = -5 m/s is her velocity (she moves backward, so the negative sign)

m_2 = 50 kg is the mass of the boy

v_2 is the velocity of the boy

As calculated in part b), we also know that the total momentum of the girl and the boy is

p_f = 0 (2)

By combining eq(1) and eq(2) we get

0=m_1 v_1 + m_2 v_2

And solving for v2 we find the velocity of the boy:

v_2=-\frac{m_1 v_1}{m_2}=-\frac{(30)(-5)}{50}=+3 m/s

and the positive sign means he is moving forward.

d)

We can solve this part by applying the impulse theorem, which states that the change in momentum of an object is equal to the product between the force applied on it and the duration of the collision:

\Delta p = F\Delta t

where

\Delta p is the change in momentum

F is the force

\Delta t is the time during which the force is applied

In this problem:

\Delta t = 2.5 s

For the boy, the change in momentum is:

\Delta p = m_2 (v_2 - u_2)

And since

m_2 = 50 kg\\u_2 = 0 m/s\\v_2 = 3 m/s

We have

\Delta p = (50)(3-0)=150 kg m/s

So, the force exerted between the boy and the girl is:

F=\frac{\Delta p}{\Delta t}=\frac{150}{2.5}=60 N

8 0
3 years ago
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