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olya-2409 [2.1K]
2 years ago
14

A car advertisement states that a certain car can accelerate from rest to 70 km/h in 7 seconds. Find the car’s acceleration. Use

the following formula:
Variable
Equation
Solve

Physics
1 answer:
tino4ka555 [31]2 years ago
5 0
Answer should be variable
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The resolution of a camera or other optical system is determined by the relationship between what two scales?
devlian [24]

Answer:

d.The wavelength of light and the size of the aperture

Explanation:

<em>The resolution power of an optical system is the smallest distance between two points that the device can distinguish clearly.</em>

It has the following relationship:

r=\frac{\lambda}{2n}

where:

r = minimum resolvable distance

n = numerical aperture

\lambda= wavelength of the light used for viewing

From above mathematical equation it is clear that:

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(Note, that smaller the value of "r" the more finer details of the image visible through the device.)

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Where is the planet moving faster?
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Endorphins are generated in the body during exercise, which leads to better emotional health true or false
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8 0
3 years ago
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Which example shows an endothermic reaction?
Nata [24]

Answer:

reactants --> products + thermal energy

Explanation:

Heat is absorbed in endothermic reaction.

6 0
2 years ago
Does the horizontal distance d travelled by the ball depend on the height of release? If it does depend on the height, what is t
elena-s [515]

Answer:

Explanation:

Yes , the horizontal distance travelled by the ball will depend upon the height of release .

When a ball is thrown at some angle from a height , it has two components , the vertical component and horizontal component . The ball goes in horizontal direction due to its horizontal component . Its vertical component has no role to play .  But the horizontal range covered by the body thrown

depends upon the duration of time in which it remains in air . The longer it remains in air , the greater distance it can cover horizontally .

Horizontal distance covered = t x horizontal velocity

If V be the velocity of throw and Vx be its horizontal component

Horizontal distance covered = t x Vx

Now t depends upon the height . If height rises , time of fall will increase so horizontal distance covered will increase .

If h be the height from which the body is thrown , Vy be the vertical upward component of initial velocity

from the relation

s = ut + 1/2 at²

h = - Vy t  + 1/2 at²

As h increases , t will increase and therefore horizontal distance covered will increase. If the ball has only  horizontal velocity initially , Vy = 0

h = 1/2 gt²

t = \sqrt{\frac{2h}{g} }

Horizontal distance covered  = t x Vx

= \sqrt{\frac{2h}{g} } \times  V_x

From this expression also

Horizontal distance covered is proportional to \sqrt{h} .

7 0
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