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Stolb23 [73]
2 years ago
9

Please help! I'm begging anyone! This is urgent! These are the problems in physics I am having difficulty with!

Physics
1 answer:
spin [16.1K]2 years ago
7 0

Answer:

1.

Distance = 0.921 meters

2.

Work = 13.9 kJ

3.

The neighbor

Double your work

Explanation:

1.

Work = Force × Distance

Distance = Work / Force

Distance = 174J /189 N

Distance = 0.921 meters

2.

Work = force × distance

Work = (613 N) (22.6 m)

Work = 13,900 J

Work = 13.9 kJ

3.

Work is a product of force and distance, expressed as W=Fd where W is work in Nm, F is applied force and d is the distance in m

Since your neighbor pushes 4 times then you just push 1m when he pushes 4m, that is an example. Also, since the neighbor only exerts half the force i.e. 0.5N then you exert full force of 1N

Work from your neighbor will be 4d*0.5F=2dF

Work from you will be dF

Clearly, 2dF=2(dF) hence the neighbor exerts double work

https://brainly.in/question/9922561

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postnew [5]

Answer:

I think it is the 3 option

7 0
3 years ago
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Find the length (in m) of an organ pipe closed at one end that produces a fundamental frequency of 494 Hz when air temperature i
elena-14-01-66 [18.8K]

Answer:

0.173 m.

Explanation:

The fundamental frequency of a closed pipe is given as

fc = v/4l .................. Equation 1

Where fc = fundamental frequency of a closed pipe, v = speed of sound  l = length of the pipe.

Making l the subject of the equation,

l = v/4fc ................ Equation 2

also

v = 331.5×0.6T ................. Equation 3

Where T = temperature in °C, T = 18.0 °c

Substitute into equation 3

v = 331.5+0.6(18)

v = 331.5+10.8

v = 342.3 m/s.

Also given: fc = 494 Hz,

Substitute into equation 2

l = 342.3/(4×494)

l = 342.3/1976

l =0.173 m.

Hence the length of the organ pipe = 0.173 m.

7 0
3 years ago
A van has a weight of 4000 lb and center of gravity at Gv. It carries a fixed 900 lb load which has a center of gravity at Gl. I
natulia [17]

Answer:

 x = 25 / μ     [ ft]

Explanation:

To solve this exercise we can use Newton's second law.

Let's set a reference system where the x axis is parallel to the road

Y axis  

       N_B + N_A - W_van - W_load = 0

       N_B + N_A = W_van + W_load

X axis

     fr = ma

     a = fr / m

the total mass is

        m = (W_van + W_load) / g

the friction force has the expression

      fr = μ N_{total}

      fr = μy (W_van + W_load)

we substitute

      a = μ (W_van + W_load)    \frac{g}{W_van + W_load}

      a = μ g

taking the acceleration let's use the kinematic relations where the final velocity is zero

       v² = v₀² - 2 a x

       0 = v₀² -2a x

        x = \frac{v_o^2}{2a}

        x = \frac{v_o^2}{2 \mu g}

        x = \frac{40^2}{2 \ 32 \  \mu}

        x = 25 / μ     [ ft]

5 0
3 years ago
How many million Christmas trees were sold in the year 2000?
Sergio039 [100]

Explanation:

Christmas tree production occurs worldwide on Christmas tree farms, in artificial tree factories and from native strands of pine and fir trees. Christmas trees, pine and fir trees purposely grown for use as a Christmas tree, are grown on plantations in many western nations, including Australia, the United Kingdom and the United States. In Australia, the industry is relatively new, and nations such as the United States, Germany and Canada are among world leaders in annual production.

Great Britain consumes about 8 million trees annually, while in the United States between 35 and 40 million trees are sold during the Christmas season. Artificial Christmas trees are mostly produced in the Pearl River delta area of China. Christmas tree prices were described using a Hotelling-Faustmann model in 2001, the study showed that Christmas tree prices declined with age and demonstrated why more farmers do not price their trees by the foot. In 1993, economists made the first known demand elasticity estimates for the natural Christmas tree market.

5 0
3 years ago
What is the kinetic energy of a 0.15 kg baseball that is moving with a velocity of 50 m/s?
goblinko [34]
Using the equation:

ke \:  =  \frac{1}{2} m{v}^{2}
ke  =   \frac{1}{2} (0.15) {(50)}^{2}
ke  = 188  \: (3sf)


Ans: 188 J
7 0
3 years ago
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