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Stolb23 [73]
2 years ago
9

Please help! I'm begging anyone! This is urgent! These are the problems in physics I am having difficulty with!

Physics
1 answer:
spin [16.1K]2 years ago
7 0

Answer:

1.

Distance = 0.921 meters

2.

Work = 13.9 kJ

3.

The neighbor

Double your work

Explanation:

1.

Work = Force × Distance

Distance = Work / Force

Distance = 174J /189 N

Distance = 0.921 meters

2.

Work = force × distance

Work = (613 N) (22.6 m)

Work = 13,900 J

Work = 13.9 kJ

3.

Work is a product of force and distance, expressed as W=Fd where W is work in Nm, F is applied force and d is the distance in m

Since your neighbor pushes 4 times then you just push 1m when he pushes 4m, that is an example. Also, since the neighbor only exerts half the force i.e. 0.5N then you exert full force of 1N

Work from your neighbor will be 4d*0.5F=2dF

Work from you will be dF

Clearly, 2dF=2(dF) hence the neighbor exerts double work

https://brainly.in/question/9922561

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Explanation:

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z(t) = -(6.5 \frac{m}{s^2}) t^2, t\geq 0

Part a

In order to find the velocity we need to take the first derivate for the position function like this:

z'(t) =v(t) = -13t

Now we can replace the velocity for t=1.75 s

v(1.75s) = -13*1.75 =-22.75 \frac{m}{s}

For t = 3.0 s we have:

v(3.0s) = -13*3.0 =-39 \frac{m}{s}

Part b

For this case we can find the average velocity with the following formula:

v_{avg}= \frac{z_f - z_i}{t_f -t_i}

And we can find the positions for the two times required like this:

z_f = z(3.0s) = -(6.5 \frac{m}{s^2}) (3.0s)^2=-58.5m

z_i = z(1.75s) = -(6.5 \frac{m}{s^2}) (1.75s)^2=-19.906m

And now we can replace and we got:

V_{avg}= \frac{-58.5 -(-19.906) m}{3-1.75 s}= -30.875 \frac{m}{s}

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