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zaharov [31]
3 years ago
7

PLEASE HELP IM CONFUSED

Physics
1 answer:
Fittoniya [83]3 years ago
3 0

Sound waves can be used in a similar way to "see" things. After turning on a sound source, we can look at the pattern of reflected sound waves that bounce back to us. Our own ears and brain don't process sound into mental pictures.


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20 POINTS!!!
hram777 [196]
I think its inductance. If its not then I think its none of the above
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3 years ago
Which form of Kepler’s third law can you use to relate the period T and radius r of a planet in our solar system as long as the
ser-zykov [4K]

T2=r In the form of Kepler's law that can use to relate the period T and radius of the planet in our solar systems

<u>Explanation:</u>

<u>Kepler's third law:</u>

  • Kepler's third law states that For all planets, the square of the orbital

     period (T) of a planet is proportional to the cube of the average orbital    radius (R).

  • In simple words T (square) is proportional to the R(cube) T²2 ∝1 R³3
  • T2 / R3 = constant = 4π ² /GM

      where G = 6.67 x 10-11 N-m2 /kg2

        M = mass of the foci body

8 0
4 years ago
Why should the substage condenser not be included in computing the magnification?
Leni [432]
The reason as to why the substage condenser does not need to be included in computing the magnification and the only component needed is the ocular lens and the objective lenses is because the condenser is only responsible for gathering light and it does not contribute with the magnification of the object under the microscope.
5 0
3 years ago
Read 2 more answers
Two wires, each of length 1.3 m, are stretched between two fixed supports. On wire A there is a second-harmonic standing wave wh
UNO [17]

Answer:

Explanation:

Given

Length of each wire L=1.3\ m

On wire A second harmonic frequency is given by

f_2_{a}=2\times (\frac{v}{2L})

where f=frequency

v=velocity of wave

L=length of wire

v_a=f_2\times L

v_a=640\times 1.3=832\ m/s

For wire B third harmonic is given by

f_3_{b}=3\times (\frac{v}{2L})

v_b=\frac{2L}{3}\cdot f_3_{b}

v_b=\frac{2\times 1.3}{3}\times 640=554.66\ m/s

3 0
4 years ago
You pull a suitcase along the floor by exerting 43N at an angle. The force of friction is 27 N and the suitcase moves at a const
Mumz [18]

The angle of the force is 51.1^{\circ}

Explanation:

To solve this problem, we can apply Newton's second law along the horizontal direction of motion of the suitcase:

\sum F_x = ma_x

where

\sum F_x is the net force along the x-axis

m is the mass of the suitcase

a_x is the acceleration along the x-axis

The suitcase is moving at constant speed, so the acceleration is zero:

a_x=0

Therefore the net force must also be zero:

\sum F_x = 0 (1)

We have two forces acting along the horizontal direction:

- The component of the push (forward) in the horizontal direction, F cos \theta, with

F = 43 N

\theta = angle of the force with the horizontal

- The  force of friction, F_f = 27 N, backward

So the net force can be written as

\sum F_x = F cos \theta - F_f (2)

Combining (1) and (2),

F cos \theta - F_f = 0

And so we can find the angle:

\theta = cos^{-1}(\frac{F_f}{F})=cos^{-1}(\frac{27}{43})=51.1^{\circ}

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

8 0
3 years ago
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