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2 years ago

What is the free-fall acceleration on a planet where the period of a 1.07 m long pendulum is 2.02 s?

Physics

1 answer:

sergeinik [125]2 years ago

5 0

Answer:

10.34 m/s^2

Explanation:

length, L = 1.07 m

Time period, T = 2.02 s

The formula of the time period of the pendulum is

$T = 2\pi \sqrt{\frac{L}{g}}$

where, g is the free fall acceleration on that planet.

$g=4\pi ^{2}\frac{L}{T^{2}}$

$g=4\pi ^{2}\frac{1.07}{2.02^{2}}$

g = 10.34 m/s^2

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2 years ago

A tank contains 350 liters of fluid in which 10 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu

aleksandr82 [10.1K]

Answer:

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Brine with concentration of 1g/L is pouring in at the rate of 5L/min so the salt income rate is 5 g/min

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Answer:

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