What is the free-fall acceleration on a planet where the period of a 1.07 m long pendulum is 2.02 s?
1 answer:
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Answer:
The distance between the person and the balloon after 2 seconds the person starts walking is changing on 4.47 m/s
Explanation:
The relative position between the balloon and the person is found using Galileo's relativity principle:
(1)
with Rb the position of the balloon and Rp the position of the person respect with the origin (See Figure 1). Because we don’t have those positions but we know the constant velocities, we can relate the positions (R) with the velocities (v) with the kinematic equation:
(2)
So equation (1) is:
(3)
with and
the unitary vectors on y and x direction respectively.
We see from our initial condition (See figure 2) that:
(4)
So if we put this on (3) and divide by time we have:
(5)
But we are interested in how fast a distance is changing, and that is a speed so:
Answer:
The impulse on the object is 60Ns.
Explanation:
Impulse is defined as the product of the force applied on an object and the time at which it acts. It is also the change in the momentum of a body.
F = m a
F = m()
⇒ Ft = m( -
)
where: F is the dorce on the object, t is the time at which it acts, m is the mass of the object, is its initialvelocity and
is the final velocity of the object.
Therefore,
impulse = Ft = m( -
)
From the question, m = 3kg, = 0m/s and
= 20m/s.
So that,
Impulse = 3 (20 - 0)
= 3(20)
= 60Ns
The impulse on the object is 60Ns.