Answer:
Mass released = 8.6 g
Given data:
Initial number of moles nitrogen= 0.950 mol
Initial volume = 25.5 L
Final mass of nitrogen released = ?
Final volume = 17.3 L
Formula:
V₁/n₁ = V₂/n₂
25.5 L / 0.950 mol = 17.3 L/n₂
n₂ = 17.3 L× 0.950 mol/25.5 L
n₂ = 16.435 L.mol /25.5 L
n₂ = 0.644 mol
Initial mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.950 mol × 28 g/mol
Mass = 26.6 g
Final mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.644 mol × 28 g/mol
Mass = 18.0 g
Mass released = initial mass - final mass
Mass released = 26.6 g - 18.0 g
Mass released = 8.6 g
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Answer:
λ = 8.716 mm
Explanation:
Given:
- d = 10 cm
- Q >= 5 degrees
Find:
- Find the shortest wavelength of light for which this apparatus is useful
Solution:
- The formula that relates the split difference and angle of separation between successive fringes is given by:
d*sin(Q) = n*λ
Where,
λ: wavelength
d: split separation
Q: angle of separation between successive fringes
m: order number.
- Since this apparatus only shows the first order light so m =1
- the shortest possible wavelength corresponds to:
d*sin(Q) = λ
λ = 0.1*sin(5)
λ = 8.716 mm
Answer:
Displacement is 565.69 m at 45° west of north
Explanation:
Let north represent positive y axis and east represent positive x axis.
We have journey started from 600 N. Michigan Avenue, and walked 3 blocks toward north, 4 blocks toward west, and 1 block toward north to a train station.
3 blocks toward north = 300 j m
4 blocks toward west = -400 i m
1 blocks toward north = 100 j m
Total displacement = -400 i + 400 j m
Magnitude

Direction,

Direction is 45° west of north.
Displacement is 565.69 m at 45° west of north
Answer:MATTER IS ANYTHING THAT HAS VOLUME AND MASS. ALL MATTER TAKES UP SPACE. THE AMOUNT OF SPACE TAKEN UP, OR OCCUPIED, BY AN OBJECT IS KNOWN AS THE OBJECT'S VOLUME. THE CURVE THAT YOU SEE AT THE LIQUID'S SURFACE HAS A SPECIAL NAME - THE MENISCUS.
Explanation:
Answer:
Z
Explanation:
The figure represented the ray diagrams produced by a convex (converging lens). The image will appear at the point where the purple ray and the orange ray meet, so at point Z.
As we see from the picture, the image will be:
- Real (because it is behind the lens, and it can be projected on a screen)
- Inverted (the image is upside down)
- Larger than the object (we can see it by noticing that the distance between the point of intersection purple-orange ray and the axis is larger than the size of the object)