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LiRa [457]
4 years ago
9

What is the formula for beryllium chloride?

Chemistry
2 answers:
Free_Kalibri [48]4 years ago
7 0
The formula of beryllium chloride is BeCL2
goldfiish [28.3K]4 years ago
6 0
BeCL2 is the answer to the questiom
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The dehydrogenation of benzyl alcohol to make the flavoring agent benzaldehyde is an equilibrium process described by the equati
valkas [14]

Answer:

(a) p_{C6H5CH2OH}=2.14x10^{-3}atm

(b) Dissociation =0.99

Explanation:

Hello,

(a) In this case, for the given chemical reaction, the law of mass action becomes:

Kc=\frac{[C6H5CHO][H2]}{[C6H5CH2OH]}

In such a way, as 1.20 g of benzyl alcohol are placed into a 2.00-L vessel, the initial concentration is:

[C6H5CH2OH]_0=\frac{1.20g*\frac{1mol}{108.14g} }{2.00L} =5.55x10^{-3}M

Hence, by writing the law of mass action in terms of the change x due to equilibrium:

Kc=\frac{(x)(x)}{5.55x10^{-3}-x}=0.558

Solving for x by using a quadratic equation one obtains:

x=5.50x10^{-3}M

Thus, the equilibrium concentration of benzyl alcohol is computed:

[C6H5CH2OH]_{eq}=5.55x10^{-3}M-5.50x10^{-3}M=5x10^{-5}M

With that concentration the partial pressure results:

p_{C6H5CH2OH}=[C6H5CH2OH]_{eq}RT =5x10^{-5}\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*523K \\p_{C6H5CH2OH}=2.14x10^{-3}atm

(b) Now, the fraction of benzyl alcohol that is dissociated relates its equilibrium concentration with its initial concentration:

Dissociation=\frac{C6H5CH2OH_{eq}}{C6H5CH2OH_0} =\frac{5.50x10^{-3}M}{5.55x10^{-3}M} =0.99

Best regards.

3 0
3 years ago
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Why pie bond are not perticipate in hybridaization​
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The first bond between two atoms is always a sigma bond and the other bonds are always pi bonds and a hybridized orbital cannot be involved in a pi bond. Thus we need to leave one electron (in case of Carbon double bond) to let the Carbon have the second bond as a pi bond.
3 0
3 years ago
Describe in general terms the structure of ionic solids such as nacl
allochka39001 [22]
<span>Ionic compounds are chemical compounds in which ions are held together in a lattice structure by ionic bonds. They have a high melting and boiling point, and they have a high hardness and are very brittle. The cations and anions are stuck together in a sense. So in this case, sodium (Na) is attracted to Chlorine (Cl).</span>
8 0
4 years ago
One way to increase the rate of a reaction occurring in solution is to stir the solution. How does this increase the rate of the
riadik2000 [5.3K]
<span>A. It increases the number of collisions between molecules.

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7 0
3 years ago
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In calculating the concentration of [Cu(NH3)4]2+ from [Cu(H2O)4]2+, the stepwise formation constants are as follows: K1=1.90×104
pashok25 [27]

Answer:

Kf = 1.11x10¹³

Explanation:

The value of Kf for a multistep process that involves an equilibrium at each step, is the multiplication of the constant of the equilibrium of each step.

Kf = K1xK2xK3xK4

Kf = 1.90x10⁴ x 3.90x10³ x 1.00x10³ x 1.50x10²

Kf = 1.11x10¹³

4 0
3 years ago
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