Why pie bond are not perticipate in hybridaization

1 answer:

3 0

The first bond between two atoms is always a sigma bond and the other bonds are always pi bonds and a hybridized orbital cannot be involved in a pi bond. Thus we need to leave one electron (in case of Carbon double bond) to let the Carbon have the second bond as a pi bond.

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Write the chemical symbol for three different atoms or atomic cations with 22 electrons

damaskus [11]

Answer:

Explanation:

To write the chemical symbol for an atom or cation with 22 electrons, we must understand some few things about an atom.

An atom is made up of positively charged paticles called protons which are located in the nucleus. The neutrons do not have any charges and are they reside together in the nucleus with the protons.

Electrons are negatively charged particles which orbits the nucleus.

Titanium in its neutral state is the 22nd element on the periodic table and it has 22 electrons.

Vanadium is the the 23rd element on the periodic table. If it loses an electron, it becomes positively charged and it is a cation.

Chromium is the 24th element on the periodic table. A loss of two electrons makes the net electrons remaining on it 22.

The symbols are:

₂₂Ti

₂₃V¹⁺

₂₄Cr²⁺

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A very small country that has managed to stay independent of their larger neighbors. (Example: Vatican City)

Yuliya22 [10]

First option (Independent State)

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3 years ago

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Matthew records the temperature outside for one day. From 10:00 a.m. to 12:00 p.m., the temperature rises 4°C. From 12:00 p.m. t

d1i1m1o1n [39]

Answer:will drop 4°c

Explanation:

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3 years ago

Butanal, an aldehyde, can be made from 1-bromobutane, but it requires two reactions in sequence. What are the two reagents that

hammer [34]

Answer:

See explanation and image attached

Explanation:

My aim is to convert 1-bromobutane to butanal. The first step is to react the 1-bromobutane substrate with water. This reaction occurs by SN2 mechanism to yield 1-butanol. Hence reagent A is water.

1-butanol is now reacted with an oxidizing agent such as acidified K2Cr2O7 (reagent B) to yield butanal. Note that primary alkanols are oxidized to alkanals.

These sequence of reactions are shown in the image attached.