Hello!
The concentration of the final solution when a<span> chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water is
0,3 MTo calculate that, you'll need to use the dilution law, where initial and final concentrations are M1 and M2 respectively, and initial and final volumes are V1 and V2, as shown below.
Keep in mind that the final volume is the sum of the 200 mL of water and the 50 mL of H</span>
₂SO₄ that were added by the teacher. 
Have a nice day!
Arranged in a lattice structure which results in the formation of a crystal
Yes, if you look at the molecular structure of ethanol, or even just evaluate the name you should be able to predict that ethanol will burn, thus producing energy.
Ethanol has a pretty simple molecular structure. The important part is the Oxygen single bonded to a Hydrogen at the end of the molecule. This O-H bond classifies ethanol as an alcohol. You can also tell that ethanol is an alcohol because both end with the same letters (ol). From everyday experience you will probably know that alcohol is flammable and burns readily. Thus, ethanol will burn and produce energy.
I hope this helps!
Answer:
true
Explanation:
I'm not sure why cause I dont know how to explain but it's TRUE
Answer:
D
Explanation:
The sample must contain impurity that is lower in atomic mass to sodium and since potassium has higher atomic mass to sodium, the answer is the sample contains NaCl and LiCl. We are sure already that the sample is not pure which rules out option a and option b contains sodium iodide which cannot contribute to the increase in chlorine