<span>The force of attraction by which terrestrial bodies tend to fall toward the center of the earth strongly. If i'm wrong, correct me. otherwise i hope this helped.</span>
Answer:
makinig ka kasi sa titser mo tas intindihin mo bobo
Answer:
Distance = 85.3 miles
displacement = 0
Explanation:
The total distance covered to grandma's house is 42.6 miles as recorded by the odometer. The same distance would be covered when returning to the base. Hence;
Total distance for the round trip = 42.6 + 42.6 = 85.2 miles
Since the trip was a round trip, the displacement is zero because the family returned to their initial location.
The acceleration of gravity on Earth is 9.8 m/s² .
The speed of a falling object keeps increasing smoothly,
in such a way that the speed is always 9.8 m/s faster than
it was one second earlier.
If you 'drop' the penny, then it starts out with zero speed.
If you also start the clock at the same instant, then
After 1.10 sec, Speed = (1.10 x 9.8) = 10.78 meters/sec
After 1.85 sec, Speed = (1.85 x 9.8) = 18.13 meters/sec
But you want this second one given in a different unit of speed.
OK then:
= (18.13 meter/sec) x (3,600 sec/hr) x (1 mile/1609.344 meter)
= (18.13 x 3,600 / 1609.344) (mile/hr) = 40.56 mph (rounded)
We did notice that in an apparent effort to make the question
sound more erudite and sophisticated, you decided to phrase
it in terms of 'velocity'. We can answer it in those terms, if we
ASSUME that there is no wind, and the penny therefore doesn't
acquire any horizontal component of motion on its way down.
With that assumption in force, we are able to state unequivocally
and without fear of contradiction that each 'speed' described above ...
with the word 'downward' appended to it ... does become a 'velocity'.
For the temperature 321 K, the temperature is 118.13 degree Fahrenheit.
<u>Explanation:</u>
degree Fahrenheit = (K - 273.15) * (9/5) + 32
Fahrenheit is a thermodynamic temperature scale, where the freezing point of water is 32 degree Fahrenheit. Based upon the definitions of the Centigrade scale and the experimental evidence, the absolute zero is -273.15 degree Celsius.
degree Fahrenheit of 321 K = (321 - 273.15) * (1.8) + 32
= 118.13 degree Fahrenheit.
