Answer:
The entropy change of carbon dioxide = 0.719 kJ/k
Explanation:
Given:
1.5 m - 3 insulated rigid tank contains 2.7 kg of carbon dioxide at 100 kPa
The objective is to determine the entropy change of carbon dioxide
Formula used:
ΔS=
Solution:
On considering,
ΔS=
On substituting the values,
ΔS=
ΔS=0.719 kJ/k
The correct answer is 2.73.
HF is a weak acid which partially dissociates to release H+ and F-
HF → H⁺ + F⁻
Initial 0.0050 0 0
Change -x +x +x
Equilibrium 0.0050–x +x +x
Solve by using the equilibrium expression: = [H⁺] [F⁻]/ [HF]
6 .8 x 10⁻⁴= x. x / 0.0050 –x
6 .8 x 10⁻⁴= x² /0.0050
x² = 6 .8 x 10⁻⁴ x 0.0050
x² = 3.4 x 10⁻⁶
x = 3.4 x 10⁻⁶
[H⁺] = 1.84 x 10⁻³
pH = - log [H⁺] = - log (1.84 x 10⁻³)
pH = 2.73
Answer:
1.9×10^20
Explanation:
ϕ = number of reaction events /number of photons absorbed
ϕ= 0.26
Energy= power× time
885×10^-3×10×60= 531J
But E= nhc/λ
n= number of photons
h= planks constant
c= speed of light
λ= wavelength
n= Eλ/hc
n= 531×280×10^-9/6.6×10^-34 ×3×10^8
n= 7.5×10^20
Therefore
From
ϕ = number of reaction events /number of photons absorbed
Number of reaction events= 0.26×7.5×10^20
= 1.95×10^20
Answer:
Number of neutrons and stability
Explanation:
An isotope of an element is basically the same element but with different number of neutrons. For example here, boron can exist in the forms of boron-10 and boron-11, and so the latter would have one more neutron than the former one.
Adding an extra neutron may or may not disrupt the strong force that much, and so the half-life and stability of the new isotope can be slightly different than its most stable one.
Answer:
55.18 L
Explanation:
First we convert 113.4 g of NO₂ into moles, using its molar mass:
- 113.4 g ÷ 46 g/mol = 2.465 mol
Then we<u> use the PV=nRT formula</u>, where:
- P = 1atm & T = 273K (This means STP)
- R = 0.082 atm·L·mol⁻¹·K⁻¹
Input the data:
- 1 atm * V = 2.465 mol * 0.082atm·L·mol⁻¹·K⁻¹ * 273 K
And <u>solve for V</u>:
