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3 years ago

2+2=4 and the. You add 7

Chemistry

1 answer:

Marat540 [252]3 years ago

8 0

Do you mean 4+7 if yes it’s 11

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What is the volume of a sample if the density is 2.35 g/mL and the mass is 33.67 g?

lawyer [7]

Density=2.35g/mL
Mass=33.67g

$\\ \star\sf\longmapsto Density=\dfrac{Mass}{Volume}$

$\\ \star\sf\longmapsto Volume=\dfrac{Mass}{Density}$

$\\ \star\sf\longmapsto Volume=\dfrac{33.67}{2.35}$

$\\ \star\sf\longmapsto Volume=14.32mL$

6 0

3 years ago

Why does water float on corn syrup

NISA [10]

Answer:

density.

Explanation:

A cubic centimeter of water weighs 1 gram. Since a cubic centimeter of vegetable oil weighs less than 1 gram, oil will float on water. Corn syrup is more dense than water so 1 cubic centimeter of corn syrup weighs more than 1 gram. Therefore, corn syrup sinks in water.

5 0

3 years ago

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Do you think taking trips to the Earth's core will ever be possible?

sweet-ann [11.9K]

Answer:

No.

Explanation:

The average distance to the center is over 6300km.

3 0

3 years ago

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4. Magnesium and oxygen undergo a chemical reaction to

erastovalidia [21]

Answer:

About 16.1 grams of oxygen gas.

Explanation:

The reaction between magnesium and oxygen can be described by the equation:
$\displaystyle 2\text{Mg} + \text{O$_2$} \longrightarrow 2\text{MgO}$

24.4 grams of Mg reacted with O₂ to produce 40.5 grams of MgO. We want to determine the mass of O₂ in the chemical change.

Compute using stoichiometry. From the equation, we know that two moles of MgO is produced from every one mole of O₂. Therefore, we can:

Convert grams of MgO to moles of MgO.
Moles of MgO to moles of O₂
And moles of O₂ to grams of O₂.

The molecular weights of MgO and O₂ are 40.31 g/mol and 32.00 g/mol, respectively.

Dimensional analysis:

$\displaystyle 40.5\text{ g MgO} \cdot \frac{1\text{ mol MgO}}{40.31\text{ g MgO}} \cdot \frac{1\text{ mol O$_2$}}{2\text{ mol MgO}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}$

In conclusion, about 16.1 grams of oxygen gas was reacted.

You will obtain the same result if you compute with the 24.4 grams of Mg instead:

$\displaystyle 24.4\text{ g Mg}\cdot \frac{1\text{ mol Mg}}{24.31\text{ g Mg}} \cdot \frac{1\text{ mol O$_2$}}{1\text{ mol Mg}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}$

3 0

2 years ago

HELP PLZ ASAP<br> will give brainliest

horrorfan [7]

Answer:

I believe that it would be the third option down.

Explanation:

The thermal energy is in constant motion in the COOLER room, and when the desired temperature in the room is reached, it stops.

8 0

3 years ago