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Marat540 [252]
3 years ago
9

Solid carbon (C) can burn in oxygen (O2). Select

Chemistry
1 answer:
babunello [35]3 years ago
3 0

Answer:

OCO

Another way of writing CO₂

Explanation:

A reaction equation has <u>reactants on the left</u> and <u>products on the right</u>.

The reactants are carbon and oxygen. The product is carbon dioxide.

C + O₂ → CO₂

You might see the equation both ways.

C + O₂ → OCO

C + O₂ in the products would mean no reaction has occurred. The problem can <u>solid carbon can burn in oxygen</u>, so a reaction will occur. For no reaction, you would put "NR" in the products.

<u>OCO is the structural way of writing CO₂.</u> Both have one carbon atom (C) and two oxygen atoms (O).

C + 2O is not possible. Oxygen, if alone, has to be at least O₂ because it's a <u>diatomic molecule</u>.

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Calculate the pH at of a 0.10 Msolution of anilinium chloride . Note that aniline is a weak base with a of . Round your answer t
notsponge [240]

The question is incomplete, here is the complete question:

Calculate the pH at of a 0.10 M solution of anilinium chloride (C_6H_5NH_3Cl) . Note that aniline (C6H5NH2) is a weak base with a pK_b of 4.87. Round your answer to 1 decimal place.

<u>Answer:</u> The pH of the solution is 5.1

<u>Explanation:</u>

Anilinium chloride is the salt formed by the combination of a weak base (aniline) and a strong acid (HCl).

To calculate the pH of the solution, we use the equation:

pH=7-\frac{1}{2}[pK_b+\log C]

where,

pK_b = negative logarithm of weak base which is aniline = 4.87

C = concentration of the salt = 0.10 M

Putting values in above equation, we get:

pH=7-\frac{1}{2}[4.87+\log (0.10)]\\\\pH=5.06=5.1

Hence, the pH of the solution is 5.1

8 0
3 years ago
From observing the plant and animal cell diagrams above, which cell seemed to have more of a regular structure?
Tasya [4]

Answer:

the green one

Explanation:

3 0
4 years ago
Which transition by an electron will release the greatest amount of energy? answer soon please ​
alexira [117]

Answer:

When electron jumps from high energy level to lower energy level.

Explanation:

The elctronic transition from one energy level to another energy level within the atom, always involve energy transitions.

The energy released or absorbed by electronic transition is always discrete and is called as " Photon". It means when electron jumps from when energy level to another energy level the energy released or absorbed is treated as photon emitted or absorbed.

When an electron jumps from higher energy level to a lower energy level, a photon of specific wavelength and specific energy is emitted in other words we can say that energy is released or emitted.

The energy of photon emitted or absorbed is easily calculated using Rydberg Formula which is simply the energy difference between the two energy levels and is given as under;

Ephoton = Eo ( 1 / n1^2 - 1 / n2 ^ 2)

In the above formula n1 is the initial energy level of electron and n2 is the final energy level of electron.

Eo = 13.6 eV ( Here "o" in Eo is in subscripts)

In n1 and n2 1 and 2 are in the subscripts.

^ represents that the disgits after them are exponents.

So by just putting the values of energy levels n1 and n2 we can easily calculate the value of energy of photon ( energy due to electronic transition) and compare the results that which transition will give high energy photon and which will give low energy photon.

3 0
4 years ago
How many grams of O2 are required to produce 5 mol CO2
maxonik [38]
I did the math i got 220 grams
7 0
3 years ago
Atrazine is an herbicide widely used for corn and is a common groundwater pollutant in the corn-producing regions of the United
riadik2000 [5.3K]

Answer:

0.94

Explanation:

Let's assume that the total sample of the soil is 1 cm³; which has a porosity of 0.4 cm³; then the original sample of the soil will be 0.6 cm³

The mass  of the soil particles in 1 cm³ of soil + water = 0.75 g

The fraction of the total atrazine can be calculated by the expression;

Total atrazine =C_w(\frac{g}{mL})*V_w(mL)+C_{(soil)}(\frac{g}{soil})*M_{(soil)}(gsoil)

Also; C_{(soil)}(\frac{g}{soil})= K_{oc}(\frac{mL}{gOC})*f_{oc} (\frac{gOC}{gsoil})*C_w(\frac{g}{mL})

NOTE THAT: K_{oc}( \frac{mL}{gOC})=K_{oc}\frac{L}{kgOC}

Total atrazine can now be calculated as:

C_w*0.4+K_{oc}f_{oc}C_w*0.75 = \frac{C_{soil}*M_{soil}}{Total atrazine}

=\frac{K_{oc}f_{oc}C_w*M_{soil}}{C_w*0.4+K_{oc}f_{oc}C_w*0.75} = \frac{0.75*K_{oc}f_{oc}}{0.4+K_{oc}f_{oc}*0.75}

= \frac{10^{2.52}*0.025*0.75}{0.4+10^{2.52}*0.025*0.75}

= 0.94

Thus,the fraction of total atrazine that will be adsorbed to the soil = 0.94.

3 0
4 years ago
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