Answer:
Rectangular path
Solution:
As per the question:
Length, a = 4 km
Height, h = 2 km
In order to minimize the cost let us denote the side of the square bottom be 'a'
Thus the area of the bottom of the square, A = 
Let the height of the bin be 'h'
Therefore the total area, 
The cost is:
C = 2sh
Volume of the box, V = 
(1)
Total cost, 
(2)
From eqn (1):
Using the above value in eqn (1):
Differentiating the above eqn w.r.t 'a':
For the required solution equating the above eqn to zero:
a = 4
Also
The path in order to minimize the cost must be a rectangle.
This is most likely True. However, it could be also False. Let me explain.
There are many air pollutants that can be found outdoors and indoors. It does depend on what kind of indoor environment we're talking about. And also what kind of outdoor environment we're talking about. In both cases it depends on the context. If the indoor environment is quite toxic, then of course, there would be less cancer-causing air pollutants for a person outside. And the same is true for the other way around.
Answer:
option a
Explanation:
Light is an electromagnetic wave which can travel in vacuum as well as any medium. The speed of light is maximum in vacuum. The electromagnetic wave travels by oscillating electric and magnetic field to the direction of motion of wave.
On the other hand, sound waves are mechanical waves which can only travel in a medium as they can only move forward by oscillating material particles.
Thus, the student should conclude option a.
Answer:
The speed of the stone when it is 4.66 m higher is 236.057 m/s.
Explanation:
Given the initial velocity and vertical distance, we can use the fourth kinematic equation (
) to find v final, or the v to the left of the equal sign. We know 
(initial velocity) is 24.7 m/s, y (change in vertical distance) is 4.66 m, and a is another way to write g (acceleration due to gravity), or 9.8 
.
From here you could plug in the values and solve for v final, but to make the solving process simpler, we can simplify the given equation, <em>then </em>plug in the known values.
To isolate v final, we can take the square root of 
and do the same to the right side of the equation. Therefore, we can find v final with: 
, where v initial is outside of the square root because it squared...
If we plug in the known values to the simplified equation, we get: 
The final answer is 236.057 m/s.
Projectile motion contains both horizontal and vertical motion.
