Question

the flux through the coils of a solenoid changes from 6.78*10^-4 wb to 1.33*10^-4 wb in 0.0333 s if the solenoid has 605 loops how much emf is generated​

Answer 1

The electric and magnetic field ( emf ) generated given the number of loops in the solenoid is 9.90 V.

Given the data in the question;

• $\delta \theta_1 = 6.78*10^{-4}Wb$

• $\delta \theta_2 = 1.33*10^{-4}Wb$

• $\delta t = 0.0333s$

• $N = 605$

Electric and magnetic fields (EMF)

Emf are invisible energy regions also called radiation, associated with the use of electrical power and various forms of lighting.

From Faraday's law; emf E is expressed as;

$emf = -N\frac{\delta \theta }{\delta t}$

Where N is number of loops, $\delta \theta$ is change in magnetic flux ( $\delta \theta_2 - \delta \theta_1$ ) and $\delta t$ is change in time.

First we determine the change in flux through each loop;

$\delta \theta$ =  ( $\delta \theta_2 - \delta \theta_1$ )

$\delta \theta = (1.33 * 10^{-4} Wb) - (6.78 * 10^{-4} Wb)\\\\\delta \theta = -0.000545$

Now, we substitute our values into the expression above

$emf = -N\frac{\delta\theta}{\delta t} \\\\emf = (-605) * (\frac{-0.000545}{0.0333}) \\\\emf = (-605) * (-0.016366)\\\\emf = 9.90V$

Therefore, the electric and magnetic field ( emf ) generated given the number of loops in the solenoid is 9.90 V.

Learn more about  electric and magnetic field emf: brainly.com/question/23765088