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PIT_PIT [208]
3 years ago
13

Which term represents a chemical reaction?

Chemistry
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

vaporization

Explanation:

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How is electronegativity related to covalent bonding?
Zolol [24]

Answer:

Atoms must have similar electronegativities in order to share electrons in a covalent bond.

Explanation:

Covalent bonding is one of the bondings that occurs between the atoms of elements. It is the bonding in which atoms share their valence electrons with one another. However, the ELECTRONEGATIVITY, which is the ability of an atom to be attracted to electrons play a major role in the formation of covalent bonds.

When atoms of different electronegativities combine, the more electronegative atom pulls more electrons towards itself, hence, an IONIC bond is formed. However, when the electronegativities of the atoms are similar, the sharing of their electrons becomes stronger. Hence, ATOMS MUST HAVE SIMILAR ELECTRONEGATIVITIES in order to share electrons in a covalent bond.

5 0
3 years ago
Read 2 more answers
For the reaction: N2O5(g) \longrightarrow⟶ 2NO2(g) + 1/2O2(g)
ivanzaharov [21]
The given equation from the problem above is already balance,
                                 N2O5 ---> 2NO2 + 0.5O2
Since, in every mole of N2O5 consumed, 2 moles of NO2 are formed, we can answer the problem by multiplying the given rate, 7.81 mol/L.s with the ratio.
                    (7.81 mol/L.s) x (2 moles NO2 formed/ 1 mole of N2O5 consumed)
                       = 15.62 mol/L.s
The answer is the rate of formation of NO2 is approximately 15.62 mol/L.s. 
5 0
3 years ago
At what temperature does ice start to melt
Delicious77 [7]

Answer:

Explanation:

The answer is 32°F or 0° Celsius.

Hope it helped you.

5 0
2 years ago
An insulated container contains 0.3 kg of water at 20 degrees C. An alloy with a mass of 0.090 kg and an initial temperature of
Lorico [155]

Answer:

The specific heat of the alloy is 2.324 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of water = 0.3 kg = 300 grams

Temperature of water = 20°C

Mass of alloy = 0.090 kg

Initial temperature of alloy = 55 °C

The final temperature = 25°C

The specific heat of water = 4.184 J/g°C

<u>Step 2:</u> Calculate the specific heat of alloy

Qlost = -Qwater

Qmetal = -Qwater

Q = m*c*ΔT

m(alloy) * c(alloy) * ΔT(alloy) = -m(water)*c(water)*ΔT(water)

⇒ mass of alloy = 90 grams

⇒ c(alloy) = the specific heat of alloy = TO BE DETERMINED

⇒ ΔT(alloy) = The change of temperature = T2 - T1 = 25-55 = -30°C

⇒ mass of water = 300 grams

⇒ c(water) = the specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature = T2 - T1 = 25 - 20 = 5 °C

90 * c(alloy) * -30°C = -300 * 4.184 J/g°C * 5°C

c(alloy) = 2.324 J/g°C

The specific heat of the  alloy is 2.324 J/g°C

3 0
3 years ago
Please help me with this homework
KengaRu [80]

Answer:

The answer is C density.

8 0
2 years ago
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