Answer:
Cs and I
Explanation:
Salts are formed when an ionic bond is formed between two elements in the compound. Let us recall that the kind of bond formed between any two elements depends on the magnitude of electronegativity difference between the two elements.
Among the options listed, the highest degree of electronegativity difference occurs for the bond between Cs and I. This implies that this bond is ionic and the combination of the two elements will lead to salt formation.
Answer:
To break down the nucleus of an atom
Explanation:
Remember to change from one element to another, is necessary to add protons, neutrons and electrons,in most of the cases.
The take an electron from an atom you need certain energy, but they are in the outside part of the atom so is not as much energy as the one is necessary to take one neutron or proton from the inside part of an atom.
In this way, is a must to have a combination of pressure and heat to destabilize an atom and take some of this subatomic particles.
Answer:
Part A = The mass of sulfur is 6.228 grams
Part B = The mass of 1 silver atom is 1.79 * 10^-22 grams
Explanation:
Part A
Step 1: Data given
A mixture of carbon and sulfur has a mass of 9.0 g
Mass of the product = 27.1 grams
X = mass carbon
Y = mass sulfur
x + y = 9.0 grams
x = 9.0 - y
x(molar mass CO2/atomic mass C) + y(molar mass SO2/atomic mass S) = 22.6
(9 - y)*(44.01/12.01) + y(64.07/32.07)
(9-y)(3.664) + y(1.998)
32.976 - 3.664y + 1.998y = 22.6
-1.666y = -10.376
y = 6.228 = mass sulfur
x = 9.0 - 6.228 = 2.772 grams = mass C
The mass of sulfur is 6.228 grams
Part B
Calculate the mass, in grams, of a single silver atom (mAg = 107.87 amu ).
Calculate moles of 1 silver atom
Moles = 1/ 6.022*10^23
Moles = 1.66*10^-24 moles
Mass = moles * molar mass
Mass = 1.66*10 ^-24 moles *107.87
Mass = 1.79 * 10^-22 grams
The mass of 1 silver atom is 1.79 * 10^-22 grams
It is the crust, the least dense layer.
Answer:
(a) ml = 0, ±1, ±2
(b) ml = 0
(c) ml = 0, ±1, ±2, ±3, ±4
Explanation:
The rules for electron quantum numbers are:
1. Shell number, 1 ≤ n
2. Subshell number, 0 ≤ l ≤ n − 1
3. Orbital energy shift, -l ≤ ml ≤ l
4. Spin, either -1/2 or +1/2
So in our exercise,
(a) l = 2; equivalent with with sublevel <em>d</em>
-l ≤ ml ≤ l, ml = 0, ±1, ±2, equivalent with dxy, dxz, dyz, dx2-y2, dz2
(b) n = 1;
n = 1, only 01 level
l = 0, equivalent with sublevel <em>s</em>
ml = 0
(c) n = 4, l = 3.
l = 3, equivalent with sublevel <em>f</em>
ml = 0, ±1, ±2, ±3, ±4
