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kompoz [17]
1 year ago
11

I NEED HELP ASAP!!!!!! LIKE RIGHT NOW PLEASE HELP!!!!! TwT

Chemistry
1 answer:
Alex1 year ago
3 0

Thermometer D, because it measures accurately to the tens place. Hence, option B is correct.

<h3>What is temperature?</h3>

The degree of hotness or coldness is measured on a definite scale.

Accuracy: It is defined as the closeness of a measured value to a standard or known value.

For Example: If the mass of a substance is 50 kg and one person weighed 48 kg and another person weighed 55 kg. Then, the weight measured by the first person is more accurate.

Precision: It is defined as the closeness of two or more measurements to each other.

For Example: If you weigh a given substance five times and you get 1.8 kg each time. Then the measurement is said to be precise.

The level of precision is determined by the maximum number of decimal places.

As per the question, the thermometer D has markings 40°, 45° and 50° at equal intervals and there are four small markings equally spaced in between the numbers and thermometer D has markings 40°, 45° and 50° at equal intervals but there are no small markings equally spaced in between the numbers. That means thermometer D measures temperature more accurately than thermometer C.

Thermometer D, because it measures accurately to the tens place. Hence, option B is correct.

Learn more about the thermometer here:

brainly.com/question/14900550

#SPJ1

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Find the pHpH of a solution prepared from 1.0 LL of a 0.15 MM solution of Ba(OH)2Ba(OH)2 and excess Zn(OH)2(s)Zn(OH)2(s). The Ks
charle [14.2K]

Answer:

pH  = 13.09

Explanation:

Zn(OH)2 --> Zn+2 + 2OH-   Ksp = 3X10^-15

Zn+2 + 4OH-   --> Zn(OH)4-2   Kf = 2X10^15

K = Ksp X Kf

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Concentration of OH⁻ = 2[Ba(OH)₂] = 2 * 0.15 = 3 M

                Zn(OH)₂ + 2OH⁻(aq)  --> Zn(OH)₄²⁻(aq)

Initial:           0             0.3                      0

Change:                      -2x                     +x

Equilibrium:               0.3 - 2x                 x

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6 = x/(0.3 -2x)(0.3 -2x)

6(0.09 -1.2x + 4x²) = x

0.54 - 7.2x + 24x² = x

24x² - 8.2x + 0.54 = 0

Upon solving as quadratic equation, we obtain;

x = 0.089

Therefore,

Concentration of (OH⁻) = 0.3 - 2x

                                    = 0.3 -(2*0.089)

                                  = 0.122

pOH = -log[OH⁻]

         = -log 0.122

          = 0.91

pH = 14-0.91

     = 13.09

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