Answer: The mole ratio of Zn to ZnO is 3: 3.
Explanation:
According to law of conservation of mass, mass can be neither be created nor be destroyed. The mass on reactant side must be equal to the mass on product side. Thus the atoms of each element on both side of the reaction must be same.
The balanced chemical reaction is:
Here 3 moles of Zn combine with 2 moles of 
to give 1 mole of 
and 3 moles of 
. Thus the mole ratio of Zn to ZnO is 3: 3.
Answer:
Radioactive isotopes are widely used in medical field
Explanation:
Radioactive isotopes are widely used in medical field.
Radiations emitted by radioactive isotopes or used to kill the microorganism in food and to increase the shelf life of food.
Cobalt-60 is used to treat the cancer.
Iodine-131 is used to check the activity of thyroid.
Technetium-99 also used for the thyroid.
Phosphorus-32 is used to detect the cancer specially in skin and eyes.
Xenon-133 is used for lungs imaging.
Au-198 is used to diagnose the liver disease.
Co-60 is used as gamma ray irradiation of tumor.
In industry radioactive isotopes are used to measure the thickness of materials.
Answer:
2 E16 Hz or 2 * 10^16 Hz
Explanation:
The formula to determine frequency is f = c / λ.
f = frequency
c = speed of light
λ = wavelength
f = 3E8 / 1.5E-8
f = 2E16
This makes sense because UV light exists roughly
between 8E14 Hz and 3E16 Hz ----- 2E16 Hz falls in that range
For the given molecule, we are asked to give-
- The electron configuration of an isolated B atom
- The electron configuration of an isolated F atom
- Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride
- valence orbitals, if any, remain unhybridized on the B atom.
- The electron configuration of an isolated B atom:
as atomic number of B is 5
electronic configuration will be [He] 2s² 2p¹
- The electron configuration of an isolated F atom:
as atomic number of F is 9
electronic configuration will be [He] 2s² 2p5
- Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride will be sp2.
as the one s and two of p orbital from the valance shell will hybridised to make 3 hybrid orbital of B resulting in 3 B-F bonds.
- valence orbitals, if any, remain unhybridized on the B atom will be 1
To know more about hybrisisation:
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Answer:
c. ceramic
Explanation:
because b d and a are metals c is not
