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3 years ago

For liquids, which of the following factors affect vapor pressure? Check all that apply: volume temperature

1 answer:

5 0

I believe the correct answer from the choices listed above is the second option. For liquids, it is the temperature that affects vapor pressure. <span>The </span>vapor pressure<span> of any substance increases non-linearly with </span>temperature<span> according to the Clausius–Clapeyron </span>relation<span>. Hope this helps. Have a nice day.</span>

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I need help please <33

Aliun [14]

Answer:

Option 3 is correct.

The atomic nucleus of each element has a unique number of protons. Therefore, the energy of the electron layers of the atoms of each element is unique.

If we have the energy released from each electron transfer between the layers of the atom, we can identify the element.

4 0

2 years ago

Calculate the volume in cm^3 of 325.0 dg of alcohol. Alcohol has a density of 0.785g/mL.

Masteriza [31]

Answer:
106 mL

Explanation:
In order to be able to answer this question, you must understand what the density of a substance tells you.
The density of a substance is nothing more than the mass of that substance that occupies one unit of volume.
In your case, the density of ethanol is given in Grams per milliliter, which means that one unit of volume will be
1 mL
.
So, ethanol has a density of
0.785 g mL
−
1
, which is equivalent to saying that if you take exactly
1 mL
of ethanol and weigh it, you will end up with a mass of
0.785 g
.
Now, you know that the volume you're using has a mass of
83.3 g
. Well, if you get
0.785 g
for every
1 mL
of ethanol, it follows that this much mass will correspond to a volume of
83.3
g ethanol
⋅
ethanol's density

1 mL
0.785
g ethanol
=
106.11 mL
Rounded to three sig figs, the answer will be
V
ethanol
=
106 mL

Hope this helps

5 0

2 years ago

How many grams of Na2SO4 should be weighed out to prepare 0.5L of a 0.100M solution?

Nezavi [6.7K]

Answer:

7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100 M solution.

Explanation:

First of all the molecular weight of Na2SO4 is 142.08 gram.Now we all know that if the molecular weight of a compound is dissolved in 1000ml or 1 litee of water then the strength of that solution becomes 1 M.

According to the given question we have to prepare 0.100 M solution

1000 ml of solution contain 142.08×0.1= 14.208 gram Na2SO4

1 ml of solution contain 14.208÷1000= 0.014 gram

0.5L or 500ml of solution contain 0.014×500= 7gram Na2SO4.

So it can be stated that 7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100M solution.

3 0

2 years ago

If oxygen, symbol o, undergoes a covalent bond it wants to form how many bonds

polet [3.4K]

Oxygen has 16 bonds in total

5 0

3 years ago

Read 2 more answers

In ironmaking, iron metal can be separated from iron ore (Fe2O3) by heating the ore in a blast furnace in the presence of coke,

mel-nik [20]

The limiting reactant is iron ore, the theoretical yield of iron metal is 701.344 kg, and the theoretical yield of carbon dioxide is 413.292 kg.

<h3>Stoichiometric problem</h3>

From the equation of the reaction:

$2 Fe_2O_3(s) + 3 C(s) --- > 4 Fe(s) + 3 CO_2(g)$

The mole ratio of iron ore to carbon is 2:3.

Mole of 1000 kg of iron ore = 1000000/159.69

= 6,262 moles

Mole of 120 kg carbon = 120000/12

= 10,000 moles

Thus, it appears that the carbon is in excess while the iron ore is limited in availability.

The mole ratio of the iron ore and the iron produced is 1:2. Thus, the equivalent number of moles of iron produced will be:

6,262 x 2 = 12,524 moles

Mass of 12,524 moles of iron = 12,524 x 56

= 701,344 g or 701.344 kg

Thus, the theoretical yield of iron is 701.344 kg.

The mole ratio of the iron ore and the carbon dioxide produced is 2:3. The equivalent mole of carbon dioxide produced will be:

6,262 x 3/2 = 9,393 moles

Mass of 9,393 moles carbon dioxide = 9,393 x 44

= 413,292 or 413.292 kg

The theoretical yield of carbon dioxide is, therefore, 413.292 kg.

More on stoichiometric problems can be found here: brainly.com/question/14465605

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3 0

1 year ago