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vesna_86 [32]
2 years ago
5

How were the compounds that formed when calcium ion solution was mixed with the anion solutions different from the compounds tha

t formed when barium ion solution was mixed with the anion solutions?

Chemistry
1 answer:
givi [52]2 years ago
6 0

A confirmatory test of sodium hydroxide and potassium chromate can be used to distinguish between a solution of calcium ion and barium ion.

The test for cations can be used to distinguish calcium ion from barium ion.

  • Calcium ion (Ca²⁺) forms a white precipitate with a drop of sodium hydroxide which is insoluble in excess.
  • Barium ion (Ba²⁺) forms a yellow precipitate with potassium chromate.

Thus, a confirmatory test of sodium hydroxide and potassium chromate can be used to distinguish between a solution of calcium ion and barium ion.

Learn more about about confirmatory test of cations here: brainly.com/question/1969246

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calculate pressure exerted by 1.255 mol of CI2 in a volume of 5.005 L at a temperature 273.5 k using ideal gas equation
balu736 [363]

Answer:

The pressure is 5.62 atm.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case:

  • P= ?
  • V= 5.005 L
  • n= 1.255 mol
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= 273.5 K

Replacing:

P* 5.005 L= 1.255 mol* 0.082 \frac{atm*L}{mol*K} *273.5 K

Solving:

P=\frac{1.255 mol* 0.082 \frac{atm*L}{mol*K} *273.5 K}{5.005 L}

P= 5.62 atm

<u><em>The pressure is 5.62 atm.</em></u>

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