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vesna_86 [32]
2 years ago
5

How were the compounds that formed when calcium ion solution was mixed with the anion solutions different from the compounds tha

t formed when barium ion solution was mixed with the anion solutions?

Chemistry
1 answer:
givi [52]2 years ago
6 0

A confirmatory test of sodium hydroxide and potassium chromate can be used to distinguish between a solution of calcium ion and barium ion.

The test for cations can be used to distinguish calcium ion from barium ion.

  • Calcium ion (Ca²⁺) forms a white precipitate with a drop of sodium hydroxide which is insoluble in excess.
  • Barium ion (Ba²⁺) forms a yellow precipitate with potassium chromate.

Thus, a confirmatory test of sodium hydroxide and potassium chromate can be used to distinguish between a solution of calcium ion and barium ion.

Learn more about about confirmatory test of cations here: brainly.com/question/1969246

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What volume of 1.10 M SrCl2 is needed to prepare 525 mL of 5.00 mM SrCl2?
grigory [225]

Answer:- 2.39 mL are required.

Solution:- It's a dilution problem and to solve this type of problems we use the dilution equation:

M_1V_1=M_2V_2

Where, M_1 and M_2 are molarities of concentrated and diluted solutions and V_1 and V_2 are their respective volumes.

M_1 = 1.10M

M_2 = 5.00mM = 0.005M    (since, mM stands for milli molar and M stands for molar. 1M = 1000mM)

V_1 = ?

V_2 = 525 mL

Let's plug in the given values in the formula:

1.10M(V_1)=0.005M(525mL)

V_1=(\frac{0.005M*525mL}{1.10M})

V_1=2.39mL

So, 2.39 mL of 1.10M are needed to make 525 mL of 5.00mM solution.

7 0
3 years ago
Help me out ! What’s the answer
Anni [7]

Answer:

true

Explanation:

5 0
2 years ago
Calculate the number of moles in the following: 2.8 X 10^24 atoms of Cl2
vova2212 [387]

Answer:

<h3>The answer is 4.65 moles</h3>

Explanation:

To find the number of moles given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 2.8 × 10²⁴ atoms of Cl2

So we have

n =  \frac{2.8 \times  {10}^{24} }{6.02 \times  {10}^{23}  }  \\  = 4.65116279069...

We have the final answer as

<h3>4.65 moles</h3>

Hope this helps you

7 0
3 years ago
Please give me the reasons of the solution!
irinina [24]

1. The answer is option E, that is None of the above is correct.

As a polymer becomes more crystalline,

its melting point doesn't decreases, its density doesn't decreases, its stiffness doesn't decreases and its yield stress doesn't decreases.

2. The answer is option B, that is the molecules are arranged in sheets, with their long axes parallel and their ends aligned as well.

In the smectic A liquid-crystalline phase, molecules are arranged in sheets, with their long axes parallel and their ends aligned as well.

3.  For a substitutional alloy to form, the two metals combined must have similar atomic radii and chemical bonding properties.

6 0
2 years ago
Why are the oxidation and reduction half-reactions separated in an<br> electrochemical cell?
Mrac [35]

Answer:

The half-cells separate the oxidation half-reaction from the reduction half-reaction and make it possible for current to flow through an external wire.

Explanation:

7 0
3 years ago
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